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CalebBeavers
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A certain bacteria population is known to triple every 90 minutes. Suppose that there are initially 80 bacteria.
What is the size of the population after t hours?
 one year ago
 one year ago
CalebBeavers Group Title
A certain bacteria population is known to triple every 90 minutes. Suppose that there are initially 80 bacteria. What is the size of the population after t hours?
 one year ago
 one year ago

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freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
If you know the doubling formula, you can just convert \[P2^{t/k} \to P3^{t/k} \] and use it that way.
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
So if this was doubling instead of tripling you would have \[P(t) = (80)2^{t/90}\] since you want this with respect to hours and not minutes you would convert the 90 minutes to hours or 1.5 so \[P(2) = 80 \times 2^{t/1.5}\] Now just convert this to tripling instead of doubling.
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
And that should be P(t) not P(2). Sorry.
 one year ago

CalebBeavers Group TitleBest ResponseYou've already chosen the best response.0
No idea what that is...its online homework. I think im supposed to use A(t)=(A_0)e^(kt)
 one year ago

CalebBeavers Group TitleBest ResponseYou've already chosen the best response.0
\[A(t)=A _{0}e ^{kt}\]
 one year ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
You can use that equation if you want to. It's just harder and more difficult. If, however, there is a population whose growth doubles for a given time span, you can represent the growth by \[A(t) = A_0 2^{t/k}\] where k represents the time it takes to "double". If it was tripling every time span you would use a 3 instead of a 2.
 one year ago
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