Here's the question you clicked on:
CalebBeavers
A certain bacteria population is known to triple every 90 minutes. Suppose that there are initially 80 bacteria. What is the size of the population after t hours?
If you know the doubling formula, you can just convert \[P2^{t/k} \to P3^{t/k} \] and use it that way.
So if this was doubling instead of tripling you would have \[P(t) = (80)2^{t/90}\] since you want this with respect to hours and not minutes you would convert the 90 minutes to hours or 1.5 so \[P(2) = 80 \times 2^{t/1.5}\] Now just convert this to tripling instead of doubling.
And that should be P(t) not P(2). Sorry.
No idea what that is...its online homework. I think im supposed to use A(t)=(A_0)e^(kt)
\[A(t)=A _{0}e ^{kt}\]
You can use that equation if you want to. It's just harder and more difficult. If, however, there is a population whose growth doubles for a given time span, you can represent the growth by \[A(t) = A_0 2^{t/k}\] where k represents the time it takes to "double". If it was tripling every time span you would use a 3 instead of a 2.