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ksaimouli Group Title

(a)increasing (b) decreasing (c)local extreme values

  • 2 years ago
  • 2 years ago

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  1. ksaimouli Group Title
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    |dw:1353980630180:dw|

    • 2 years ago
  2. ksaimouli Group Title
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    i took derivative =0 i got \[+-\sqrt{2}\]

    • 2 years ago
  3. Brittni0605 Group Title
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    Take the derivative, find the critical points, draw a number line, find y values of your critical points, determine local extrema and increasing/decreasing intervals.

    • 2 years ago
  4. ksaimouli Group Title
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    should i need to include the domain restriciton in numberline @Brittni0605

    • 2 years ago
  5. Brittni0605 Group Title
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    If a restriction was given than yes.

    • 2 years ago
  6. ksaimouli Group Title
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    +-2

    • 2 years ago
  7. ksaimouli Group Title
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    no restriction is given

    • 2 years ago
  8. ksaimouli Group Title
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    when i take derivative i set denominator=0 i got +-2

    • 2 years ago
  9. Brittni0605 Group Title
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    Ok, so your domain is negative infinity to infinity

    • 2 years ago
  10. ksaimouli Group Title
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    yup

    • 2 years ago
  11. ksaimouli Group Title
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    |dw:1353980936825:dw|

    • 2 years ago
  12. ksaimouli Group Title
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    this is the derivative of teh funciton

    • 2 years ago
  13. Brittni0605 Group Title
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    Ok.

    • 2 years ago
  14. ksaimouli Group Title
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    so the critical points are|dw:1353981108528:dw|

    • 2 years ago
  15. Brittni0605 Group Title
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    Yes.

    • 2 years ago
  16. ksaimouli Group Title
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    should need to set the denominator to find domain of the function |dw:1353981161255:dw|

    • 2 years ago
  17. ksaimouli Group Title
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    |dw:1353981180565:dw|

    • 2 years ago
  18. Brittni0605 Group Title
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    Yes, good number line

    • 2 years ago
  19. ksaimouli Group Title
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    or|dw:1353981212350:dw|

    • 2 years ago
  20. ksaimouli Group Title
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    that one or this one so confused

    • 2 years ago
  21. Brittni0605 Group Title
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    The first pic.

    • 2 years ago
  22. Brittni0605 Group Title
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    You're critical values are the x values where the derivative =0 or where the derivative doesnt exist.

    • 2 years ago
  23. ksaimouli Group Title
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    then if i choose -3 to check whether it is + or - their is domain error

    • 2 years ago
  24. Brittni0605 Group Title
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    By setting the numerator equal to 0, you found where the derivative equals . By setting the denominator equal to 0, you found where the derivative doesnt exist

    • 2 years ago
  25. ksaimouli Group Title
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    yup i know that one i set the number line can u plz figure out the +and- values

    • 2 years ago
  26. ksaimouli Group Title
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    |dw:1353981465522:dw|

    • 2 years ago
  27. Brittni0605 Group Title
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    |dw:1353981469116:dw|

    • 2 years ago
  28. ksaimouli Group Title
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    so increasing=|dw:1353981723064:dw|

    • 2 years ago
  29. ksaimouli Group Title
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    dec|dw:1353981745781:dw|

    • 2 years ago
  30. Brittni0605 Group Title
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    Yes.

    • 2 years ago
  31. Brittni0605 Group Title
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    They didnt give you a domain, but bc of the type of prob, a domain was determined. You found out the function only exists between (-2,2)

    • 2 years ago
  32. ksaimouli Group Title
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    max root2 and min -root2

    • 2 years ago
  33. ksaimouli Group Title
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    so function exists (-2,2) but min and max at end enpoints undefinied am i right but it is good to check the domain

    • 2 years ago
  34. Brittni0605 Group Title
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    Um, you have to find the y values of your critical points

    • 2 years ago
  35. ksaimouli Group Title
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    i know that i simple

    • 2 years ago
  36. ksaimouli Group Title
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    esay

    • 2 years ago
  37. Brittni0605 Group Title
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    Lol, ok.

    • 2 years ago
  38. ksaimouli Group Title
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    i hate typo

    • 2 years ago
  39. ksaimouli Group Title
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    thx

    • 2 years ago
  40. Brittni0605 Group Title
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    Np. Hope I helped.

    • 2 years ago
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