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ksaimouli
 4 years ago
(a)increasing (b) decreasing (c)local extreme values
ksaimouli
 4 years ago
(a)increasing (b) decreasing (c)local extreme values

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ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353980630180:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0i took derivative =0 i got \[+\sqrt{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Take the derivative, find the critical points, draw a number line, find y values of your critical points, determine local extrema and increasing/decreasing intervals.

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0should i need to include the domain restriciton in numberline @Brittni0605

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If a restriction was given than yes.

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0no restriction is given

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0when i take derivative i set denominator=0 i got +2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, so your domain is negative infinity to infinity

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353980936825:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0this is the derivative of teh funciton

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0so the critical points aredw:1353981108528:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0should need to set the denominator to find domain of the function dw:1353981161255:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353981180565:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, good number line

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0ordw:1353981212350:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0that one or this one so confused

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You're critical values are the x values where the derivative =0 or where the derivative doesnt exist.

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0then if i choose 3 to check whether it is + or  their is domain error

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0By setting the numerator equal to 0, you found where the derivative equals . By setting the denominator equal to 0, you found where the derivative doesnt exist

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0yup i know that one i set the number line can u plz figure out the +and values

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353981465522:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353981469116:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0so increasing=dw:1353981723064:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0decdw:1353981745781:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0They didnt give you a domain, but bc of the type of prob, a domain was determined. You found out the function only exists between (2,2)

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0max root2 and min root2

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0so function exists (2,2) but min and max at end enpoints undefinied am i right but it is good to check the domain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Um, you have to find the y values of your critical points
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