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(a)increasing (b) decreasing (c)local extreme values

Mathematics
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|dw:1353980630180:dw|
i took derivative =0 i got \[+-\sqrt{2}\]
Take the derivative, find the critical points, draw a number line, find y values of your critical points, determine local extrema and increasing/decreasing intervals.

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Other answers:

should i need to include the domain restriciton in numberline @Brittni0605
If a restriction was given than yes.
+-2
no restriction is given
when i take derivative i set denominator=0 i got +-2
Ok, so your domain is negative infinity to infinity
yup
|dw:1353980936825:dw|
this is the derivative of teh funciton
Ok.
so the critical points are|dw:1353981108528:dw|
Yes.
should need to set the denominator to find domain of the function |dw:1353981161255:dw|
|dw:1353981180565:dw|
Yes, good number line
or|dw:1353981212350:dw|
that one or this one so confused
The first pic.
You're critical values are the x values where the derivative =0 or where the derivative doesnt exist.
then if i choose -3 to check whether it is + or - their is domain error
By setting the numerator equal to 0, you found where the derivative equals . By setting the denominator equal to 0, you found where the derivative doesnt exist
yup i know that one i set the number line can u plz figure out the +and- values
|dw:1353981465522:dw|
|dw:1353981469116:dw|
so increasing=|dw:1353981723064:dw|
dec|dw:1353981745781:dw|
Yes.
They didnt give you a domain, but bc of the type of prob, a domain was determined. You found out the function only exists between (-2,2)
max root2 and min -root2
so function exists (-2,2) but min and max at end enpoints undefinied am i right but it is good to check the domain
Um, you have to find the y values of your critical points
i know that i simple
esay
Lol, ok.
i hate typo
thx
Np. Hope I helped.

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