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ihatealgebrasomuch

any help? Find the range of possible values for x. ***will draw triangles***

  • one year ago
  • one year ago

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  1. ihatealgebrasomuch
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    |dw:1353985451040:dw|

    • one year ago
  2. jim_thompson5910
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    the length 6x+3 is opposite the larger angle so 4x+12 < 6x+3

    • one year ago
  3. jim_thompson5910
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    also, if you update the drawing, you get |dw:1353986053883:dw|

    • one year ago
  4. jim_thompson5910
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    so we can say that 32 - 21 < 4x+12 < 32+21 and we can say 32 - 21 < 6x+3 < 32+21

    • one year ago
  5. ihatealgebrasomuch
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    how do you find the rang from that though? @jim_thompson5910

    • one year ago
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