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laylam25
Group Title
Anyone know how to go about this problem?!
Calculate the 5unit moving average of the function. Plot the function and its moving average on the same graph, as in Example 4. (You may use graphing technology for the plot, but you should compute the moving average analytically.)
 one year ago
 one year ago
laylam25 Group Title
Anyone know how to go about this problem?! Calculate the 5unit moving average of the function. Plot the function and its moving average on the same graph, as in Example 4. (You may use graphing technology for the plot, but you should compute the moving average analytically.)
 one year ago
 one year ago

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KiwiBaby Group TitleBest ResponseYou've already chosen the best response.0
Although I'm pretty sure I have no idea how to do this problem.. I'm quite confident you didn't give enough information. What was the function?
 one year ago

laylam25 Group TitleBest ResponseYou've already chosen the best response.0
whoops yeah sorry the function is f(x) = x^(2/3)
 one year ago

KiwiBaby Group TitleBest ResponseYou've already chosen the best response.0
Ahhh, well... I still have no idea..lol. But at least someone else has a better shot at it now :) Good luck!
 one year ago

laylam25 Group TitleBest ResponseYou've already chosen the best response.0
Yeah I hope so :) thanks for the double check!
 one year ago

KiwiBaby Group TitleBest ResponseYou've already chosen the best response.0
Anytime! (:
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
similar problem http://nz.answers.yahoo.com/question/index?qid=20080810155317AACeTkQ
 one year ago

eseidl Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1}{n}\int\limits_{xn}^{x}f(t)dt\]So,\[\frac{1}{5}\int\limits_{x5}^{x}t^\frac{2}{3}dt\]and,dw:1353989867919:dw
 one year ago

laylam25 Group TitleBest ResponseYou've already chosen the best response.0
in your drawing, where did the 3/5 come from?
 one year ago

laylam25 Group TitleBest ResponseYou've already chosen the best response.0
thanks btw! :)
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[\frac23+1=\frac53\]
 one year ago

laylam25 Group TitleBest ResponseYou've already chosen the best response.0
thank you!
 one year ago
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