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Find the inflection points at x=C and x=D with C less than or equal to D?
Consider the function f(x) = x^(2)e^(9x).
I just don't know how to determine what the inflection points are after I find the second derivative.
f(x) has two inflection points at x = C and x = D with C less than or equal to D
What is C
What is D
 one year ago
 one year ago
Find the inflection points at x=C and x=D with C less than or equal to D? Consider the function f(x) = x^(2)e^(9x). I just don't know how to determine what the inflection points are after I find the second derivative. f(x) has two inflection points at x = C and x = D with C less than or equal to D What is C What is D
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.1
take the derivative twice, set it equal to zero, there are to answers one is smaller than the other, the smaller one is C and the larger one is D
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
when you get the second derivative, factor out the \(e^{9x}\) and get \[e^{9 x} (81 x^2+36 x+2)\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
\(e^{9x}\) is never zero, solve the quadratic equation you will get two zeros, those are the inflection points
 one year ago

xmasBest ResponseYou've already chosen the best response.0
Oh! Thank you! It's the quadratic function that I need to use for this problem.
 one year ago

xmasBest ResponseYou've already chosen the best response.0
And to find C and D would be by inputing it into which function?
 one year ago

xmasBest ResponseYou've already chosen the best response.0
I mean inputing the value of x.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
exactly you get two answers from the quadratic formula the smaller one C and the larger on D if you have to write both coordiates, yes, you evaluate the function at those points (the original function)
 one year ago

xmasBest ResponseYou've already chosen the best response.0
Thank you so much! This helps a whole lot!
 one year ago
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