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anonymous
 3 years ago
Find the inflection points at x=C and x=D with C less than or equal to D?
Consider the function f(x) = x^(2)e^(9x).
I just don't know how to determine what the inflection points are after I find the second derivative.
f(x) has two inflection points at x = C and x = D with C less than or equal to D
What is C
What is D
anonymous
 3 years ago
Find the inflection points at x=C and x=D with C less than or equal to D? Consider the function f(x) = x^(2)e^(9x). I just don't know how to determine what the inflection points are after I find the second derivative. f(x) has two inflection points at x = C and x = D with C less than or equal to D What is C What is D

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0take the derivative twice, set it equal to zero, there are to answers one is smaller than the other, the smaller one is C and the larger one is D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when you get the second derivative, factor out the \(e^{9x}\) and get \[e^{9 x} (81 x^2+36 x+2)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(e^{9x}\) is never zero, solve the quadratic equation you will get two zeros, those are the inflection points

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh! Thank you! It's the quadratic function that I need to use for this problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And to find C and D would be by inputing it into which function?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I mean inputing the value of x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0exactly you get two answers from the quadratic formula the smaller one C and the larger on D if you have to write both coordiates, yes, you evaluate the function at those points (the original function)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you so much! This helps a whole lot!
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