## anonymous 3 years ago Determine where f(x) intersects the x-axis. f(x)=(x+10)2−81

1. anonymous

the 2 is supposed to me an exponant...

2. anonymous

intersecting x-axis implies y-coordinate is zero, therefore eqating f(x)=0 ew get $0=(x+2)^{2}-81$ $x+2=\pm9$ x=-11,7 So the given fuction intersects x-axis at x=7 and x=-11

3. anonymous

$(x+10)^2-81=0$ $(x+10)^2=81$ $x+10=\pm\sqrt{81}=\pm9$ so $$x+10=9\iff x=-1$$ and $$x+10=-9\iff x=-19$$

4. anonymous

Thank you!