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talleymarksBest ResponseYou've already chosen the best response.0
the 2 is supposed to me an exponant...
 one year ago

sumanth4phyBest ResponseYou've already chosen the best response.1
intersecting xaxis implies ycoordinate is zero, therefore eqating f(x)=0 ew get \[0=(x+2)^{2}81\] \[x+2=\pm9\] x=11,7 So the given fuction intersects xaxis at x=7 and x=11
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
\[(x+10)^281=0\] \[(x+10)^2=81\] \[x+10=\pm\sqrt{81}=\pm9\] so \(x+10=9\iff x=1\) and \(x+10=9\iff x=19\)
 one year ago
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