Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

A rocket is fired vertically from the ground. It moves upwards with a constant acceleration of 10m/s^2 for 30 seconds, after which the fuel is consumed. After what time from the instant of firing, the rocket will attain the maximum height? (Take g=10m/s^2)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- chestercat

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

calculate the velocity of the rocket after 30 seconds.. !.. and then use your 1d kinematics to solve the problem..

- anonymous

@Mashy here will the intitial velocity be taken 0??..

- anonymous

here the options are given as 75s , 60s , 45s and 30s...so what should be the answer according to u?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

yes.. you have to take the initial velocity as zero.. and then compute the velocity after 30 seconds.. using 10m/s^2 uniform acceleration.... then do another computation by taking that newly computed velocity as the initial velocity and find time for max height.. !!

- anonymous

ohhhh...ok...let me first try that out...

- anonymous

yea.. sure :).. if you don't get the answer.. show me your work here! .. ll tell whats wrong

- anonymous

in the another calculation...i should take the acceleration as that g=10m/s^2...and in that one i should take the final velocity as 0 ..?,,,right?..

- anonymous

if in the second case i tak final velocity 0 ...then i get answer as 30 s ..easily..?.

Looking for something else?

Not the answer you are looking for? Search for more explanations.