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Akshit_math

A rocket is fired vertically from the ground. It moves upwards with a constant acceleration of 10m/s^2 for 30 seconds, after which the fuel is consumed. After what time from the instant of firing, the rocket will attain the maximum height? (Take g=10m/s^2)

  • one year ago
  • one year ago

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  1. Mashy
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    calculate the velocity of the rocket after 30 seconds.. !.. and then use your 1d kinematics to solve the problem..

    • one year ago
  2. Akshit_math
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    @Mashy here will the intitial velocity be taken 0??..

    • one year ago
  3. Akshit_math
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    here the options are given as 75s , 60s , 45s and 30s...so what should be the answer according to u?

    • one year ago
  4. Mashy
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    yes.. you have to take the initial velocity as zero.. and then compute the velocity after 30 seconds.. using 10m/s^2 uniform acceleration.... then do another computation by taking that newly computed velocity as the initial velocity and find time for max height.. !!

    • one year ago
  5. Akshit_math
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    ohhhh...ok...let me first try that out...

    • one year ago
  6. Mashy
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    yea.. sure :).. if you don't get the answer.. show me your work here! .. ll tell whats wrong

    • one year ago
  7. Akshit_math
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    in the another calculation...i should take the acceleration as that g=10m/s^2...and in that one i should take the final velocity as 0 ..?,,,right?..

    • one year ago
  8. Akshit_math
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    if in the second case i tak final velocity 0 ...then i get answer as 30 s ..easily..?.

    • one year ago
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