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anonymous
 3 years ago
homogeneous equations....how to find degree???
anonymous
 3 years ago
homogeneous equations....how to find degree???

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can u explain by example??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do we have to convert equation to y/x form everytime??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what i know is that if we have equation likedw:1354030150259:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we find degree by dw:1354030245650:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the denominator x cancels numerator x n what we get degree as 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but in another question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x^n f1(y/x)+y^n f2(x/y)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0degree is considered both + and  n

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i want to know in what form of fraction do we have to exactly convert an equation to find degree?? x/y or y/x?? hope u get what m askin

across
 3 years ago
Best ResponseYou've already chosen the best response.1A function \(f\) is said to be homogeneous of degree \(k\) if \(f(\alpha\mathbf{x})=\alpha^kf(\mathbf{x})\). In your case,\[f(\alpha x,\alpha y)=\frac{\alpha^3x^3+\alpha^3y^3}{\alpha x\alpha y}=\alpha^2\frac{x^3+y^3}{xy}=\alpha^2f(x,y).\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@across thanx for ya help aneways
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