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homogeneous to find degree???

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can u explain by example??
do we have to convert equation to y/x form everytime??

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Other answers:

what i know is that if we have equation like|dw:1354030150259:dw|
we find degree by |dw:1354030245650:dw|
its a function
say f(x,y)
the denominator x cancels numerator x n what we get degree as 2
since x has power 2
u catchin me?
but in another question
\[x^n f1(y/x)+y^-n f2(x/y)\]
degree is considered both + and - n
i want to know in what form of fraction do we have to exactly convert an equation to find degree?? x/y or y/x?? hope u get what m askin
A function \(f\) is said to be homogeneous of degree \(k\) if \(f(\alpha\mathbf{x})=\alpha^kf(\mathbf{x})\). In your case,\[f(\alpha x,\alpha y)=\frac{\alpha^3x^3+\alpha^3y^3}{\alpha x-\alpha y}=\alpha^2\frac{x^3+y^3}{x-y}=\alpha^2f(x,y).\]
@across thanx for ya help aneways

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