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LHS: use sec^2 x = 1 /cos^2 x

Thanks for answering but I still don't get it. What do you mean?

LHS = 1 + sin^2 x
-------
cos^2 x

and sin^2 x
------- = tan^2 x
cos^2 x

so LHS = 1 + tan^2 x

right

I just don't see how the cos^2x in the denomenator fits in. I'm sorry I truly suck at this :(

i introduced the cos^2x because sin^2 x/cos^2 x = tan^2 x and sec^2 x = 1/cos^2 x

OK so how would I put that together to get the answer

if you google trigonometrical identities you'll a list of them

starting from the original equation how do I use what you gave me.

well we got LHS = 1 + tan^2 x and this equals RHS sec^2 x

yw

|dw:1354034596449:dw|

above the last equal sign.... what does it say? 1/??

oh wait is it 1/cos^2x ?

yeah sister

no - they are both acceptable - just another way to do it