1 + sec^2 x sin^2 x = sec^2 x
Verify this trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

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LHS: use sec^2 x = 1 /cos^2 x

Thanks for answering but I still don't get it. What do you mean?

LHS = 1 + sin^2 x
-------
cos^2 x

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