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LHS: use sec^2 x = 1 /cos^2 x
Thanks for answering but I still don't get it. What do you mean?
LHS = 1 + sin^2 x ------- cos^2 x
and sin^2 x ------- = tan^2 x cos^2 x
so LHS = 1 + tan^2 x
ok... so let me see if this will help you help me understand this better. I know that I'm supposed to do something with the left side of the equation to make it sec^2x. correct?
I just don't see how the cos^2x in the denomenator fits in. I'm sorry I truly suck at this :(
yes these can be tricky - you must have a good knowledge of the trig identities sometimes you just try different ones to see if there are any connections - i was aiming for 1 + tan^2 x because i knew that sec^2 x = 1 + tan^2 x
i introduced the cos^2x because sin^2 x/cos^2 x = tan^2 x and sec^2 x = 1/cos^2 x
OK so how would I put that together to get the answer
if you google trigonometrical identities you'll a list of them
starting from the original equation how do I use what you gave me.
well we got LHS = 1 + tan^2 x and this equals RHS sec^2 x
yes but then again so does 1+ sec^2x sin^2x. I need to transform (1+sec^2xsin^2x) and make it read sec^2x
LHS = 1+sec^2xsin^2x) = 1 + sin^2 x ------ (because sec^2 x = 1 / cos^2 x) cos^2 x = 1 + tan^2x = sec^2 x ( because sec^2x = 1 + tan^2 x is a standard identity) = RHS
Ohhhhh got it wow! OK. Thank you so much. You see I suck so bad that even when you are plainly explaining it to me I still dont get it. But now I do. Again thank you for helping me :)
above the last equal sign.... what does it say? 1/??
oh wait is it 1/cos^2x ?
awesome.... ok thanks but why is yours different than the other one? is it wrong or is this just another way to do it
no - they are both acceptable - just another way to do it