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An object falls because of gravity at a rate of -980 cm/s^2 (- sign is indicative of a downward direction) for 10. seconds. If it starts from rest (Vo = 0) and its position starts from Do= 0.0, where is it 10. seconds later?

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  1. sumanth4phy
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    \[ S=Vt + (1/2)at^{2}\] V=0, t=10, a = -980cm/sec.sec S= -490 meters

    • one year ago
  2. minnie123
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    Thanks...! :)

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