Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

MrFrizzy

  • 3 years ago

Evaluate exactly in radians: arctan(1/sqrt(3)). I know it equals tan(x)=sqrt(3)/3 and the answer is pi/6 but I do not know why. Can someone explain?

  • This Question is Closed
  1. myininaya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\arctan(\frac{1}{\sqrt{3}})=\arctan(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}})\] The range of arctan( ) is -pi/2 to pi/2 For when do you have from -pi/2 to pi/2 that \[\tan( )=\frac{\sin( )}{\cos( )}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\]

  2. myininaya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Use unit circle.

  3. MrFrizzy
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ah, your explanation is exactly what I needed to see. I never though about the fact that the sine and cosine would have common denominators and therefore cancel. Thank you

  4. myininaya
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    np :)

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy