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MrFrizzy
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Evaluate exactly in radians: arctan(1/sqrt(3)). I know it equals tan(x)=sqrt(3)/3 and the answer is pi/6 but I do not know why. Can someone explain?
 one year ago
 one year ago
MrFrizzy Group Title
Evaluate exactly in radians: arctan(1/sqrt(3)). I know it equals tan(x)=sqrt(3)/3 and the answer is pi/6 but I do not know why. Can someone explain?
 one year ago
 one year ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\arctan(\frac{1}{\sqrt{3}})=\arctan(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}})\] The range of arctan( ) is pi/2 to pi/2 For when do you have from pi/2 to pi/2 that \[\tan( )=\frac{\sin( )}{\cos( )}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Use unit circle.
 one year ago

MrFrizzy Group TitleBest ResponseYou've already chosen the best response.0
Ah, your explanation is exactly what I needed to see. I never though about the fact that the sine and cosine would have common denominators and therefore cancel. Thank you
 one year ago
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