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Steph_Rawr352
 3 years ago
Solve the following system of equations.
x + 3y + 2z = –16
2x – y + 2z = –15
2x – 2y – z = 1
Steph_Rawr352
 3 years ago
Solve the following system of equations. x + 3y + 2z = –16 2x – y + 2z = –15 2x – 2y – z = 1

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JAVIER34
 3 years ago
Best ResponseYou've already chosen the best response.0First step is eliminate the Z x + 3y + 2z = 16 2x  y + 2z = 15  () x + 4y = 1 … (1) x + 3y + 2z = 16 x + 3y + 2z = 16 2x  2y  z = 1 x2 4x  4y  2z = 2  (+) 5x y =  14 … (2)

JAVIER34
 3 years ago
Best ResponseYou've already chosen the best response.0Second step is eliminate the Y (1) and (2) x + 4y = 1 x + 4y = 1 5x  y = 14 x 4 20x  4y = 56  (+) 19x = 57 x = 57/19 … (3) After get the X value, put in equation (2) to get the Y value 5x  y = 14  y =  14 5x y = 14 + 5 x Next after you get the X and Y, put in your first equation x + 3y + 2z = 16 2z = 16 x3y z = 8  1/2 x  3/2y then you get the Z.... sorry not much time to calculate the rest for you :)

Steph_Rawr352
 3 years ago
Best ResponseYou've already chosen the best response.0thanks you guys c:
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