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have you shown why m has to be a multiple of \(2^n\)?

No, not really

That was just the information I got from the start

To me it doesn't make much sense though :/

One more thing, how do I know that r should be odd?

it m is not a power of two, it contains at least one factor other than 2 or an odd factor

we also know that \[x^n+1\] is always factorable for positive odd integers n.

I think i understand it

I have the solution now so I need to sit down and learn the procedure.

Thank you sirm3d :)