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cbrusoe
HELP PLEASE? =)
@cbrusoe can u make factors of 98?????????
\[-\sqrt{49.2} + 3\sqrt{9.2} = -7\sqrt{2} + 9\sqrt{2} = 2\sqrt{2}\]
well find the square numbers that are factors 98 = 49 x 2 18 = 9 x 2 so you will have \[-\sqrt{49 \times 2} + \sqrt{9 \times 2} = - \sqrt{49} \times \sqrt{2} + \sqrt{9} \times \sqrt{2}\] the square root of 2 won't change but you can find the other square roots... then its like algebra... adding or subtracting like terms.