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razroz
Group Title
Evaluate the line integral f(x,y)ds along the parametric curve: f(x,y)=3x+4y^2;x=2t1, y=t+5, 1(<or=) t (<or=) 2
 2 years ago
 2 years ago
razroz Group Title
Evaluate the line integral f(x,y)ds along the parametric curve: f(x,y)=3x+4y^2;x=2t1, y=t+5, 1(<or=) t (<or=) 2
 2 years ago
 2 years ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[ds =\sqrt{(x')^2+(y')^2}\]
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
well, in this case i spose fx and fy for partials
 2 years ago

razroz Group TitleBest ResponseYou've already chosen the best response.0
so i take the partial of both x and y with respect to t and plus that under a square root next to the function f(x,y) and integrate?
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
yes, but dont forget to replace x and y with their t equations within f f(x,y)=3x+4y^2;x=2t1, y=t+5 f(t)=3(2t1)+4(t+5)^2
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
or am i mixing things up?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
ds = v(t) dt
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im mixing a vector feild in with this i believe
 2 years ago

razroz Group TitleBest ResponseYou've already chosen the best response.0
no i believe you are right, let me write it out real quick
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
you're fine @amistre64
 2 years ago

razroz Group TitleBest ResponseYou've already chosen the best response.0
so i would just get a sqrt(5) from the ds, then the function would read integral of (3(2t1)+4(t+5)^2)dt (times the sqrt(5))?
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
..... thnx ;)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
yep, but put the sqrt5 inside the integral
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
yes correct, @razroz
 2 years ago

razroz Group TitleBest ResponseYou've already chosen the best response.0
thank you so much
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good luck ;)
 2 years ago
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