Can someone help me please!? Evaluate the piecewise-defined function for the given values. If f(x) = x for x ≥ 0 x2 for x < 0 , find f(5), f(6), f(−2), and f(−3).

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Can someone help me please!? Evaluate the piecewise-defined function for the given values. If f(x) = x for x ≥ 0 x2 for x < 0 , find f(5), f(6), f(−2), and f(−3).

Mathematics
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x2 = x^2
@ sm101 for x>=0 what is f(x)=? then what is f(5)=? and f(6)=?
I don't know... ??

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for x>=0 what is f(x)=? it is f(x)=x just use the formula given then what is f(5)=? and f(6)=?.... f(5)=x and f(6)=6..
next f(x)=x^2 for x
ok.. I'll try
ok good just plug into the formula f(x)=x^2 right?
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in case you had trouble reading the question ^
I'm not sure how to substitute the f(5) and to come up with a solution
ok the picewise prob means that for x>=0 the formula you have to use is f(x)=x and for x<0 the formula you have to use is f(x)=x^2
that is for the piecewise formula here If f(x) = x for x ≥ 0 =x2 for x < 0
. If f(x) = x for x ≥ 0, the given are x=5 and x=6, therefore f(5)=5 and f(6)=6 now for f(x) =x^2 for x < 0, the given are x=-2 and x=-3 therefore f(x) =x^2 f(-2)=___? and f(-3)=___?
f(-2)=-2^2 and f(-3)=-3^2 ?
yes correct.... :D
just complete the answer what is (-2)^2=__?and (-3)^2=__?
-2^2 = 4 and -3^2 = 9
right?
justa remember for piecewise no matter how many formula they use ,, used them all :D
yess correct :D
yes! let me see if this works
what is f(5) and f(6) though?
use the formula for f(x)>=0 ,,,f(x)=x therefore f(5)+__? and f(6)=___? look up there and read, what we have done up there before.... :D
I did.. but I'm confused lol f(5)+? f(6)=6
yes sorry that was f(5)=___? :D yess you are correct f(6)=6
ok so f(5) = 5, I know this part, but then how to i find the answer?
where do i plug in the 5 and 6?
yes you are correct, and that was the answer already .... :D
plug into f(x)=x therefore f(5)=__? and f(6)=__?

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