A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Can someone help me please!?
Evaluate the piecewisedefined function for the given values.
If f(x) =
x for x ≥ 0
x2 for x < 0
, find f(5), f(6), f(−2), and f(−3).
anonymous
 3 years ago
Can someone help me please!? Evaluate the piecewisedefined function for the given values. If f(x) = x for x ≥ 0 x2 for x < 0 , find f(5), f(6), f(−2), and f(−3).

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ sm101 for x>=0 what is f(x)=? then what is f(5)=? and f(6)=?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for x>=0 what is f(x)=? it is f(x)=x just use the formula given then what is f(5)=? and f(6)=?.... f(5)=x and f(6)=6..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0next f(x)=x^2 for x<o use this formula for x<0 w/c is x=2 and x=3 therefore f(−2)=___?), and f(−3).=___?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok good just plug into the formula f(x)=x^2 right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354063436337:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0in case you had trouble reading the question ^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not sure how to substitute the f(5) and to come up with a solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok the picewise prob means that for x>=0 the formula you have to use is f(x)=x and for x<0 the formula you have to use is f(x)=x^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is for the piecewise formula here If f(x) = x for x ≥ 0 =x2 for x < 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0. If f(x) = x for x ≥ 0, the given are x=5 and x=6, therefore f(5)=5 and f(6)=6 now for f(x) =x^2 for x < 0, the given are x=2 and x=3 therefore f(x) =x^2 f(2)=___? and f(3)=___?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0f(2)=2^2 and f(3)=3^2 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just complete the answer what is (2)^2=__?and (3)^2=__?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02^2 = 4 and 3^2 = 9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0justa remember for piecewise no matter how many formula they use ,, used them all :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes! let me see if this works

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is f(5) and f(6) though?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use the formula for f(x)>=0 ,,,f(x)=x therefore f(5)+__? and f(6)=___? look up there and read, what we have done up there before.... :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I did.. but I'm confused lol f(5)+? f(6)=6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes sorry that was f(5)=___? :D yess you are correct f(6)=6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so f(5) = 5, I know this part, but then how to i find the answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where do i plug in the 5 and 6?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes you are correct, and that was the answer already .... :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0plug into f(x)=x therefore f(5)=__? and f(6)=__?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.