Can someone help me please!?
Evaluate the piecewise-defined function for the given values.
If f(x) =
x for x ≥ 0
x2 for x < 0
, find f(5), f(6), f(−2), and f(−3).

- anonymous

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- anonymous

x2 = x^2

- anonymous

@ sm101
for x>=0 what is f(x)=?
then what is f(5)=? and f(6)=?

- anonymous

I don't know... ??

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## More answers

- anonymous

for x>=0 what is f(x)=? it is f(x)=x just use the formula given
then what is f(5)=? and f(6)=?.... f(5)=x and f(6)=6..

- anonymous

next f(x)=x^2 for x

- anonymous

ok.. I'll try

- anonymous

ok good just plug into the formula f(x)=x^2 right?

- anonymous

|dw:1354063436337:dw|

- anonymous

in case you had trouble reading the question ^

- anonymous

I'm not sure how to substitute the f(5) and to come up with a solution

- anonymous

ok the picewise prob means that for x>=0 the formula you have to use is f(x)=x
and for x<0 the formula you have to use is f(x)=x^2

- anonymous

that is for the piecewise formula here
If f(x) = x for x ≥ 0
=x2 for x < 0

- anonymous

. If f(x) = x for x ≥ 0, the given are x=5 and x=6, therefore
f(5)=5 and f(6)=6
now for
f(x) =x^2 for x < 0, the given are x=-2 and x=-3
therefore
f(x) =x^2
f(-2)=___? and f(-3)=___?

- anonymous

f(-2)=-2^2 and f(-3)=-3^2 ?

- anonymous

yes correct.... :D

- anonymous

just complete the answer what is (-2)^2=__?and (-3)^2=__?

- anonymous

-2^2 = 4 and -3^2 = 9

- anonymous

right?

- anonymous

justa remember for piecewise no matter how many formula they use ,, used them all :D

- anonymous

yess correct :D

- anonymous

yes! let me see if this works

- anonymous

what is f(5) and f(6) though?

- anonymous

use the formula for f(x)>=0 ,,,f(x)=x therefore
f(5)+__? and
f(6)=___?
look up there and read, what we have done up there before.... :D

- anonymous

I did.. but I'm confused lol
f(5)+? f(6)=6

- anonymous

yes sorry that was f(5)=___? :D
yess you are correct f(6)=6

- anonymous

ok so f(5) = 5, I know this part, but then how to i find the answer?

- anonymous

where do i plug in the 5 and 6?

- anonymous

yes you are correct, and that was the answer already .... :D

- anonymous

plug into
f(x)=x therefore
f(5)=__? and
f(6)=__?

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