Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Can someone help me please!?
Evaluate the piecewisedefined function for the given values.
If f(x) =
x for x ≥ 0
x2 for x < 0
, find f(5), f(6), f(−2), and f(−3).
 one year ago
 one year ago
Can someone help me please!? Evaluate the piecewisedefined function for the given values. If f(x) = x for x ≥ 0 x2 for x < 0 , find f(5), f(6), f(−2), and f(−3).
 one year ago
 one year ago

This Question is Closed

mark_o.Best ResponseYou've already chosen the best response.1
@ sm101 for x>=0 what is f(x)=? then what is f(5)=? and f(6)=?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
for x>=0 what is f(x)=? it is f(x)=x just use the formula given then what is f(5)=? and f(6)=?.... f(5)=x and f(6)=6..
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
next f(x)=x^2 for x<o use this formula for x<0 w/c is x=2 and x=3 therefore f(−2)=___?), and f(−3).=___?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
ok good just plug into the formula f(x)=x^2 right?
 one year ago

sm101Best ResponseYou've already chosen the best response.0
in case you had trouble reading the question ^
 one year ago

sm101Best ResponseYou've already chosen the best response.0
I'm not sure how to substitute the f(5) and to come up with a solution
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
ok the picewise prob means that for x>=0 the formula you have to use is f(x)=x and for x<0 the formula you have to use is f(x)=x^2
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
that is for the piecewise formula here If f(x) = x for x ≥ 0 =x2 for x < 0
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
. If f(x) = x for x ≥ 0, the given are x=5 and x=6, therefore f(5)=5 and f(6)=6 now for f(x) =x^2 for x < 0, the given are x=2 and x=3 therefore f(x) =x^2 f(2)=___? and f(3)=___?
 one year ago

sm101Best ResponseYou've already chosen the best response.0
f(2)=2^2 and f(3)=3^2 ?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
just complete the answer what is (2)^2=__?and (3)^2=__?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
justa remember for piecewise no matter how many formula they use ,, used them all :D
 one year ago

sm101Best ResponseYou've already chosen the best response.0
yes! let me see if this works
 one year ago

sm101Best ResponseYou've already chosen the best response.0
what is f(5) and f(6) though?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
use the formula for f(x)>=0 ,,,f(x)=x therefore f(5)+__? and f(6)=___? look up there and read, what we have done up there before.... :D
 one year ago

sm101Best ResponseYou've already chosen the best response.0
I did.. but I'm confused lol f(5)+? f(6)=6
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
yes sorry that was f(5)=___? :D yess you are correct f(6)=6
 one year ago

sm101Best ResponseYou've already chosen the best response.0
ok so f(5) = 5, I know this part, but then how to i find the answer?
 one year ago

sm101Best ResponseYou've already chosen the best response.0
where do i plug in the 5 and 6?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
yes you are correct, and that was the answer already .... :D
 one year ago

mark_o.Best ResponseYou've already chosen the best response.1
plug into f(x)=x therefore f(5)=__? and f(6)=__?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.