## sm101 2 years ago Can someone help me please!? Evaluate the piecewise-defined function for the given values. If f(x) = x for x ≥ 0 x2 for x < 0 , find f(5), f(6), f(−2), and f(−3).

1. sm101

x2 = x^2

2. mark_o.

@ sm101 for x>=0 what is f(x)=? then what is f(5)=? and f(6)=?

3. sm101

I don't know... ??

4. mark_o.

for x>=0 what is f(x)=? it is f(x)=x just use the formula given then what is f(5)=? and f(6)=?.... f(5)=x and f(6)=6..

5. mark_o.

next f(x)=x^2 for x<o use this formula for x<0 w/c is x=-2 and x=-3 therefore f(−2)=___?), and f(−3).=___?

6. sm101

ok.. I'll try

7. mark_o.

ok good just plug into the formula f(x)=x^2 right?

8. sm101

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9. sm101

10. sm101

I'm not sure how to substitute the f(5) and to come up with a solution

11. mark_o.

ok the picewise prob means that for x>=0 the formula you have to use is f(x)=x and for x<0 the formula you have to use is f(x)=x^2

12. mark_o.

that is for the piecewise formula here If f(x) = x for x ≥ 0 =x2 for x < 0

13. mark_o.

. If f(x) = x for x ≥ 0, the given are x=5 and x=6, therefore f(5)=5 and f(6)=6 now for f(x) =x^2 for x < 0, the given are x=-2 and x=-3 therefore f(x) =x^2 f(-2)=___? and f(-3)=___?

14. sm101

f(-2)=-2^2 and f(-3)=-3^2 ?

15. mark_o.

yes correct.... :D

16. mark_o.

just complete the answer what is (-2)^2=__?and (-3)^2=__?

17. sm101

-2^2 = 4 and -3^2 = 9

18. sm101

right?

19. mark_o.

justa remember for piecewise no matter how many formula they use ,, used them all :D

20. mark_o.

yess correct :D

21. sm101

yes! let me see if this works

22. sm101

what is f(5) and f(6) though?

23. mark_o.

use the formula for f(x)>=0 ,,,f(x)=x therefore f(5)+__? and f(6)=___? look up there and read, what we have done up there before.... :D

24. sm101

I did.. but I'm confused lol f(5)+? f(6)=6

25. mark_o.

yes sorry that was f(5)=___? :D yess you are correct f(6)=6

26. sm101

ok so f(5) = 5, I know this part, but then how to i find the answer?

27. sm101

where do i plug in the 5 and 6?

28. mark_o.

yes you are correct, and that was the answer already .... :D

29. mark_o.

plug into f(x)=x therefore f(5)=__? and f(6)=__?