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Find all solutions to the equation in the interval [0, 2π). sin 2x - sin 4x = 0 I NEED HELP I DON'T UNDERSTAND THIS CRAP.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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srry dont really know
im only in geomerty
how helpful of you!

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Other answers:

is it multipulchoise
sin(2x) + sin(4x) = 0 sin(2x) + 2sin(2x)cos(2x) = 0 sin(2x)[1 + 2cos(2x)] = 0 sin(2x) = 0 or 2cos(2x) = -1 -> cos(2x) = -1/2 when sin(2x) = 0 2x = 0, pi, 2pi, 3pi x = 0, pi/2, pi, 3pi/2 when cos(2x) = -1/2 2x = 2pi/3, 4pi/3, 8pi/3, 10pi/3 x = pi/3, 2pi/3, 4pi/3, 5pi/3 so x = 0, pi/2, pi, 3pi/2 , pi/3, 2pi/3, 4pi/3, 5pi/3 @jim_thompson5910 is thsi correct?
sin(2x) = sin(4x) sin(2x) = sin(2*2x) sin(2x) = 2sin(2x)cos(2x) 2sin(2x)cos(2x) - sin(2x) = 0 sin(2x) * (2cos(2x) - 1) = 0 sin(2x) = 0 or cos(2x) = 1/2 x = 0 + n•π/2, π/6 + n•π, 5π/6 + n•π x = 0, π/6, π/2, 5π/6, π, 7π/6, 3π/2, 11π/6, 2π
As the king I demand you take your sluttish Profile Picture off and put something more holy. What would your parents say.
a. π/6 , π/2 , 5π/6 , 7π/6 , 3π/2, 11π/6 b. 0, π/6 , π/2 , 5π/6 , π, 7π/6 , 3π/2, 11π/6 c. 0, 2π/3, 4π/3 d. 0, π/3, 2π/3, π, 4π/3, 5π/3
as reaper i sujuest u shh or die
My lord, You people can't take a joke.
i was jst kiddn
@AFleming42 dose that help u at all??
Oh, I wasn't that is a very sluttish picture. Parents you watch what there kids wear these days.
that was a graduation party
How did you get that answer @Reaper534 ?
by the power of google hahaha
Alright well I'll take google's word on it and hope for the best!
thanks mucho(:
Your welcome :)
Glad i could help.
Lukecrayonz you are correct, so that would make the answer choice B
In that case thank you again @jim_thompson5910 !
didn't do much, Lukecrayonz did all the work really
good job @Lukecrayonz (: <3
thanks cutie can i get your number
message me(;
ernies back

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