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AFleming42

Find all solutions to the equation in the interval [0, 2π). sin 2x - sin 4x = 0 I NEED HELP I DON'T UNDERSTAND THIS CRAP.

  • one year ago
  • one year ago

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  1. Reaper534
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    srry dont really know

    • one year ago
  2. Reaper534
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    im only in geomerty

    • one year ago
  3. AFleming42
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    how helpful of you!

    • one year ago
  4. Reaper534
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    is it multipulchoise

    • one year ago
  5. Lukecrayonz
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    sin(2x) + sin(4x) = 0 sin(2x) + 2sin(2x)cos(2x) = 0 sin(2x)[1 + 2cos(2x)] = 0 sin(2x) = 0 or 2cos(2x) = -1 -> cos(2x) = -1/2 when sin(2x) = 0 2x = 0, pi, 2pi, 3pi x = 0, pi/2, pi, 3pi/2 when cos(2x) = -1/2 2x = 2pi/3, 4pi/3, 8pi/3, 10pi/3 x = pi/3, 2pi/3, 4pi/3, 5pi/3 so x = 0, pi/2, pi, 3pi/2 , pi/3, 2pi/3, 4pi/3, 5pi/3 @jim_thompson5910 is thsi correct?

    • one year ago
  6. Reaper534
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    sin(2x) = sin(4x) sin(2x) = sin(2*2x) sin(2x) = 2sin(2x)cos(2x) 2sin(2x)cos(2x) - sin(2x) = 0 sin(2x) * (2cos(2x) - 1) = 0 sin(2x) = 0 or cos(2x) = 1/2 x = 0 + n•π/2, π/6 + n•π, 5π/6 + n•π x = 0, π/6, π/2, 5π/6, π, 7π/6, 3π/2, 11π/6, 2π

    • one year ago
  7. TheKing
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    As the king I demand you take your sluttish Profile Picture off and put something more holy. What would your parents say.

    • one year ago
  8. AFleming42
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    a. π/6 , π/2 , 5π/6 , 7π/6 , 3π/2, 11π/6 b. 0, π/6 , π/2 , 5π/6 , π, 7π/6 , 3π/2, 11π/6 c. 0, 2π/3, 4π/3 d. 0, π/3, 2π/3, π, 4π/3, 5π/3

    • one year ago
  9. Reaper534
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    as reaper i sujuest u shh or die

    • one year ago
  10. TheKing
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    My lord, You people can't take a joke.

    • one year ago
  11. Reaper534
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    i was jst kiddn

    • one year ago
  12. Reaper534
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    @AFleming42 dose that help u at all??

    • one year ago
  13. TheKing
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    Oh, I wasn't that is a very sluttish picture. Parents you watch what there kids wear these days.

    • one year ago
  14. Reaper534
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    that was a graduation party

    • one year ago
  15. AFleming42
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    How did you get that answer @Reaper534 ?

    • one year ago
  16. Reaper534
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    by the power of google hahaha

    • one year ago
  17. AFleming42
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    Alright well I'll take google's word on it and hope for the best!

    • one year ago
  18. AFleming42
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    thanks mucho(:

    • one year ago
  19. TheKing
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    Your welcome :)

    • one year ago
  20. TheKing
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    Glad i could help.

    • one year ago
  21. jim_thompson5910
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    Lukecrayonz you are correct, so that would make the answer choice B

    • one year ago
  22. AFleming42
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    In that case thank you again @jim_thompson5910 !

    • one year ago
  23. jim_thompson5910
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    didn't do much, Lukecrayonz did all the work really

    • one year ago
  24. AFleming42
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    good job @Lukecrayonz (: <3

    • one year ago
  25. Lukecrayonz
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    thanks cutie can i get your number

    • one year ago
  26. AFleming42
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    message me(;

    • one year ago
  27. Reaper534
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    ernies back

    • one year ago
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