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MBrecht92

  • 3 years ago

Solve for x: 8^x = 1/6root(2)

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  1. MBrecht92
    • 3 years ago
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    I'm guessing I should change the RHS to (1/2)^(1/6.) Am I right?

  2. MBrecht92
    • 3 years ago
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    lol tkhunny saves the day again!

  3. MBrecht92
    • 3 years ago
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    Hello to you as well, sasogeek

  4. sasogeek
    • 3 years ago
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    hi :)

  5. tkhunny
    • 3 years ago
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    First, I'm not clear on your notation. Is it \(8^{x} = \dfrac{1}{6}\sqrt{2}\) or maybe \(8^{x} = \sqrt[6]{2}\) or something else?

  6. MBrecht92
    • 3 years ago
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    The latter.

  7. MBrecht92
    • 3 years ago
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    Sorry. I don't know how to type expressions like this into the field.

  8. MBrecht92
    • 3 years ago
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    Anyway..I imagine I'm supposed to end up with 2^3^x = (1/2)^(1/6)

  9. MBrecht92
    • 3 years ago
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    And then 2^3x = 2^(-1/6)

  10. tkhunny
    • 3 years ago
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    No worries. Learning just a little LaTeX can go a long way. You just have to find other ways to communicate without it. Click the [Equation] button, below, and do some experimenting.

  11. MBrecht92
    • 3 years ago
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    Alright, will do :). So...is the answer just (-1/6)/2?

  12. tkhunny
    • 3 years ago
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    Excellent! 2^(3x) is the real key to this problem's simplest solution. Same bases! If they are to be equal, the exponents must be equal. 3x = -1/6 if we started with \(\dfrac{1}{\sqrt[6]{2}}\) or 3x = 1/6 if we started with \(\sqrt[6]{2}\) or

  13. MBrecht92
    • 3 years ago
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    Oh...of course. So it's (-1/6)/3, or -1/18

  14. MBrecht92
    • 3 years ago
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    haha Thank you very much for the medal sasogeek, however undeserved it may be!

  15. MBrecht92
    • 3 years ago
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    Thank you for all of your help!

  16. sasogeek
    • 3 years ago
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    it is well deserved :) you worked your way through to get the answer ;) and u got it right as well :)

  17. MBrecht92
    • 3 years ago
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    Well, actually I got it wrong and then tkhunny guided me towards the correct answer, but I'm glad you think so!

  18. MBrecht92
    • 3 years ago
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    A good night to all!

  19. MBrecht92
    • 3 years ago
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    Though I'm sure I'll be back.

  20. sasogeek
    • 3 years ago
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    sure he did :) and that was great of him/her lol but at the end of the day, i think you deserve the medal for your effort :)

  21. MBrecht92
    • 3 years ago
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    Well, once again, thank you very much!

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