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anonymous
 4 years ago
Solve for x:
8^x = 1/6root(2)
anonymous
 4 years ago
Solve for x: 8^x = 1/6root(2)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm guessing I should change the RHS to (1/2)^(1/6.) Am I right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol tkhunny saves the day again!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hello to you as well, sasogeek

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.0First, I'm not clear on your notation. Is it \(8^{x} = \dfrac{1}{6}\sqrt{2}\) or maybe \(8^{x} = \sqrt[6]{2}\) or something else?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry. I don't know how to type expressions like this into the field.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Anyway..I imagine I'm supposed to end up with 2^3^x = (1/2)^(1/6)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And then 2^3x = 2^(1/6)

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.0No worries. Learning just a little LaTeX can go a long way. You just have to find other ways to communicate without it. Click the [Equation] button, below, and do some experimenting.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Alright, will do :). So...is the answer just (1/6)/2?

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.0Excellent! 2^(3x) is the real key to this problem's simplest solution. Same bases! If they are to be equal, the exponents must be equal. 3x = 1/6 if we started with \(\dfrac{1}{\sqrt[6]{2}}\) or 3x = 1/6 if we started with \(\sqrt[6]{2}\) or

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh...of course. So it's (1/6)/3, or 1/18

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha Thank you very much for the medal sasogeek, however undeserved it may be!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you for all of your help!

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.0it is well deserved :) you worked your way through to get the answer ;) and u got it right as well :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, actually I got it wrong and then tkhunny guided me towards the correct answer, but I'm glad you think so!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Though I'm sure I'll be back.

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.0sure he did :) and that was great of him/her lol but at the end of the day, i think you deserve the medal for your effort :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, once again, thank you very much!
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