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gcuwagirl
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Here is the related rate problem:
At noon Ship A is 150 km west of Ship B. Ship A is sailing east at 35km/h and Ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 4:00 p.m.? I can't figure the diagram to use to help with the equation. I think it is 10^2 + 100^2 = z^2 where dx/dt is 35 and dy/dt is 25. Is this correct? I was thinking I should land up with a negative answer as the distance is being reduced at this time.
 one year ago
 one year ago
gcuwagirl Group Title
Here is the related rate problem: At noon Ship A is 150 km west of Ship B. Ship A is sailing east at 35km/h and Ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 4:00 p.m.? I can't figure the diagram to use to help with the equation. I think it is 10^2 + 100^2 = z^2 where dx/dt is 35 and dy/dt is 25. Is this correct? I was thinking I should land up with a negative answer as the distance is being reduced at this time.
 one year ago
 one year ago

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sumanth4phy Group TitleBest ResponseYou've already chosen the best response.2
you are on right track and calculate dz/dt....but it would be definitely positive The distance was initially decreasing and then at a point reached it's minimum seperation and then started to increase. You cannot c all this if u think mathematically. But physics explains all this by just a imagining the figure:)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
At (12) Ship A is 150 km west of Ship B. A < 150 km  B Ship A is sailing east at 35km/h A < 150 km  B > 35km/h Ship B is sailing north at 25 km/h. ^  25 km/h A < 150 km  B > 35km/h How fast is the distance between the ships changing at 4:00 p.m.? a formula defining placement will give us a formula to derive to find speed. Looks to be the pythag thrm for a right triangle a^2 + b^2 = d^2 , implicit derivative gives 2a a' + 2b b' = 2d d' ; dividing off the common 2 and dividing by d solves for d' d' = (a a' + b b')/d
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
a = 150  4(35) b = 4(25) d = sqrt(a^2+b^2) a' is the speed of a b' is the speed of b everything is known to find d'. the speed at which the ships are moving with resoect to each other
 one year ago

gcuwagirl Group TitleBest ResponseYou've already chosen the best response.0
Thanks for your affirmations. That is very helpful
 one year ago
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