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Areesha.1D
Group Title
1) 2W=3X and W+Z=X+Y what is Y in terms of W?
(i caught myself stuck on this when reviewing, when i had gotten it right the first time around :S)
 one year ago
 one year ago
Areesha.1D Group Title
1) 2W=3X and W+Z=X+Y what is Y in terms of W? (i caught myself stuck on this when reviewing, when i had gotten it right the first time around :S)
 one year ago
 one year ago

This Question is Closed

hartnn Group TitleBest ResponseYou've already chosen the best response.1
you'll be able to find Y in terms of W and Z to get 3X in 2nd equation, you multiply W+Z=X+Y by 3 so that you can replace '3X' by '2W' (from first equation.) what u get ?
 one year ago

Areesha.1D Group TitleBest ResponseYou've already chosen the best response.0
Sure, but where does the z go?
 one year ago

Areesha.1D Group TitleBest ResponseYou've already chosen the best response.0
only in terms of W!!!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
thats what i am saying, you won't be able to find it ONLY in terms of W , it seems impossible to me..... unless more equations are given.....
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
do u understand how you will not be able to eliminate Z ??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i wonder what hba is typing from last 8 minutes...
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
@hartnn If we make more equations it is quite possible to eliminate.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
I am solving it
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ohh.. go ahead, surprise me ...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
with 2 equations, you''l only be able to eliminate 1 variable....
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Well i ended up getting their values lol and yeah @hartnn Your'e Right :)
 one year ago

Areesha.1D Group TitleBest ResponseYou've already chosen the best response.0
OMG I got it. I just misread the diagram, here:dw:1354085940249:dw
 one year ago

Areesha.1D Group TitleBest ResponseYou've already chosen the best response.0
Thats the number square associated whereas the original one was dw:1354085985283:dw
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
X=2W/3 W+Z=2W/3+Y W2W/3=YZ W/3=YZ W+Z=X+Y      W/3WZ=XZ W/3W=2W/3Z W/3W2W/3=Z W3W2W/3=Z 4W/3=Z W+Z=X+Y W4W/3=2W/3+Y
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Actually i did it.
 one year ago

Areesha.1D Group TitleBest ResponseYou've already chosen the best response.0
Lol im not going to go and evaluate that xD good for you though!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u subtracted incorrectly....
 one year ago

Areesha.1D Group TitleBest ResponseYou've already chosen the best response.0
@hartnn :O
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
that was to hba....
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
he gets Z=Z after subtraction....
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
W/3=YZ W+Z=X+Y      W/3WZ=XZ
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Oh Haha,If i wouldn't had made the mistake how could i have got the answer :P
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
A system with 4 variables and 2 equations.
 one year ago
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