## Areesha.1D 3 years ago 1) 2W=3X and W+Z=X+Y what is Y in terms of W? (i caught myself stuck on this when reviewing, when i had gotten it right the first time around :S)

1. hartnn

you'll be able to find Y in terms of W and Z to get 3X in 2nd equation, you multiply W+Z=X+Y by 3 so that you can replace '3X' by '2W' (from first equation.) what u get ?

2. Areesha.1D

Sure, but where does the z go?

3. Areesha.1D

only in terms of W!!!

4. hartnn

thats what i am saying, you won't be able to find it ONLY in terms of W , it seems impossible to me..... unless more equations are given.....

5. hartnn

do u understand how you will not be able to eliminate Z ??

6. hartnn

i wonder what hba is typing from last 8 minutes...

7. hba

@hartnn If we make more equations it is quite possible to eliminate.

8. hba

I am solving it

9. hartnn

ohh.. go ahead, surprise me ...

10. hartnn

with 2 equations, you''l only be able to eliminate 1 variable....

11. hba

Well i ended up getting their values lol and yeah @hartnn Your'e Right :)

12. Areesha.1D

OMG I got it. I just misread the diagram, here:|dw:1354085940249:dw|

13. Areesha.1D

Thats the number square associated whereas the original one was |dw:1354085985283:dw|

14. hba

X=2W/3 W+Z=2W/3+Y W-2W/3=Y-Z W/3=Y-Z W+Z=X+Y - - - - ----------- W/3-W-Z=X-Z W/3-W=2W/3-Z W/3-W-2W/3=Z W-3W-2W/3=Z -4W/3=Z W+Z=X+Y W-4W/3=2W/3+Y

15. hba

Actually i did it.

16. Areesha.1D

Lol im not going to go and evaluate that xD good for you though!

17. hba

Ahm,Ahm.

18. hartnn

u subtracted incorrectly....

19. Areesha.1D

@hartnn :O

20. hartnn

that was to hba....

21. hartnn

he gets -Z=-Z after subtraction....

22. hba

Where lol ?

23. hartnn

W/3=Y-Z W+Z=X+Y - - - - ----------- W/3-W-Z=-X-Z

24. hba