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TomLikesPhysics
 2 years ago
Best ResponseYou've already chosen the best response.0According to my book this is true: \[\sum_{k=1}^{n}1=n\] Why is this sum n and not 1 or 0 since there is nothing to sum?

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1there is. The summation notation means that 1 is added n times. So, it's 1+1+1+1+1+1+1+1...+1 {n times }=n

daftkillz
 2 years ago
Best ResponseYou've already chosen the best response.0or you could factorise quadratically but that would take way longer

TomLikesPhysics
 2 years ago
Best ResponseYou've already chosen the best response.0Why do I add the 1s since there is no index k?

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sum_{k=1}^{n}1 = 1+1+1+1+1+......+1 =n\] if there is no k, then there is none. k=1 simply means you start from first terms. in this case,it's 1

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1the k can be omitted, actually.

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sum_{k=1}^{n}=\sum_{1}^{n}\]

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1writing k is mostly a formality but in this case without the index, then we simply ignore it and just add up 1s n times

TomLikesPhysics
 2 years ago
Best ResponseYou've already chosen the best response.0Ok, now I think I get it. Thank you Shadowys for your help.
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