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  • DLS

At the same instant that a 0.50-kg ball is dropped from 25 m above Earth, a second ball, with a mass of 0.25 kg, is thrown straight upward from Earth’s surface with an initial speed of 15 m/s. They move along nearby lines and pass without colliding. At the end of 2.0 s the velocity of the center of mass of the two-ball system is:

Physics
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options??
  • DLS
A. 11 m/s, down B. 11 m/s, up C. 15 m/s, down D. 15 m/s, up E. 20 m/s, down
  • DLS
V(a)=20m/s V(b)=-5m/s

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Other answers:

Since this is multiple choice, lets use 10 m/s^2 as the acceleration due to gravity.
  • DLS
so 0.50*20+0.25*(-5)/0.75
The trick is to look at the momentum of the system after 2 seconds. So for the heavy ball, after two seconds, it has a velocity of -20 m/s.
  • DLS
10+1.25/0.75 (wil we have a minus sign or are we considering just the mag?
Thus it has a momentum of -10 kg*m/s.
  • DLS
u took downwards negative?
yaa, i took downwards negative. The light ball will have a velocity of -5 m/s (15 m/s going up minus 20 m/s due to gravity gives 5 m/s downward). So it has a momentum of -1.25 kg*m/s.
In both cases, the negative sign indicates the momentum is downward, and the sum is -11.25 kg*m/s.
Find the velocity of the system by dividing by the total mass (0.75 kg)?? then solve it and you get your answer.
  • DLS
i took downwards positive and upwards negative,im getting something different
no, always took downwards negative and upwards positive
  • DLS
v=0+10*2 v=20m/s downwards and v=15-20 v=-5m/s upwards
no!!!!
Find the velocity of the system by dividing by the total mass (0.75 kg) and you get 15 m/s down. so your answer is option C) 15 m/s up.
  • DLS
wait u messed up!!
no,, 15 m/s down.
  • DLS
im taking downwards negative and upwards positive so for the 0.25 kg ball, v=15+20=35? we are taking upwards positive right
right
  • DLS
0.25*35=8.75
  • DLS
-20+8.75
  • DLS
oh :o
  • DLS
-11.25/0.75=-15m/s
  • DLS
i see! :D
okk

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