Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

firebirdBest ResponseYou've already chosen the best response.0
if f(x) = X squared does it follow that f(a+1) = (a+1) squared
 one year ago

ASAAD123Best ResponseYou've already chosen the best response.0
replace x with (a+1).
 one year ago

firebirdBest ResponseYou've already chosen the best response.0
How do you evaluate the expresssion f(g(4)) when f(x)= 3x and g(x)= x2
 one year ago

hbaBest ResponseYou've already chosen the best response.2
@firebird Do you understand ?
 one year ago

hbaBest ResponseYou've already chosen the best response.2
So let me explain that to you We have to find f(g(4) So we have to find g(4) first g(x)=x2 then g(4)=
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
note: if f(x)=3x, g(x)=x2, then f(g(x))=3(g(x))=3(x2)
 one year ago

ASAAD123Best ResponseYou've already chosen the best response.0
f(g(x)) :substitute g(x) in x of f(x).
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
simply sub anything inside x as long it's in the domain.
 one year ago

hbaBest ResponseYou've already chosen the best response.2
@firebird Do you follow me ?
 one year ago

hbaBest ResponseYou've already chosen the best response.2
So what did you get ? g(4)=
 one year ago

firebirdBest ResponseYou've already chosen the best response.0
So under the same values of f(x) and g(x), g(f(4)) is equal to g(3(x)) which is equal to x2(3x)?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.