A community for students.
Here's the question you clicked on:
 0 viewing
firebird
 2 years ago
If f(x) = xsquared does f(a+1) = (a+1)squared
firebird
 2 years ago
If f(x) = xsquared does f(a+1) = (a+1)squared

This Question is Closed

firebird
 2 years ago
Best ResponseYou've already chosen the best response.0if f(x) = X squared does it follow that f(a+1) = (a+1) squared

firebird
 2 years ago
Best ResponseYou've already chosen the best response.0How do you evaluate the expresssion f(g(4)) when f(x)= 3x and g(x)= x2

hba
 2 years ago
Best ResponseYou've already chosen the best response.2@firebird Do you understand ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.2So let me explain that to you We have to find f(g(4) So we have to find g(4) first g(x)=x2 then g(4)=

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.0note: if f(x)=3x, g(x)=x2, then f(g(x))=3(g(x))=3(x2)

ASAAD123
 2 years ago
Best ResponseYou've already chosen the best response.0f(g(x)) :substitute g(x) in x of f(x).

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.0simply sub anything inside x as long it's in the domain.

hba
 2 years ago
Best ResponseYou've already chosen the best response.2@firebird Do you follow me ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.2So what did you get ? g(4)=

firebird
 2 years ago
Best ResponseYou've already chosen the best response.0So under the same values of f(x) and g(x), g(f(4)) is equal to g(3(x)) which is equal to x2(3x)?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.