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AGummiBear55
Group Title
PLEASE HELP me solve the inequality: –2(x – 3) ≥ 5 – (x + 3) Here's my work so far: 2(x3)>=5(x3)
2x+6>=55x+15
2x+6>=5x10
6 on both sides
2x>=5x16
5x on both sides
7x>=16
7x on both sides
That's what I'm doing but it isn't getting the right answer , I think! HELP!
 2 years ago
 2 years ago
AGummiBear55 Group Title
PLEASE HELP me solve the inequality: –2(x – 3) ≥ 5 – (x + 3) Here's my work so far: 2(x3)>=5(x3) 2x+6>=55x+15 2x+6>=5x10 6 on both sides 2x>=5x16 5x on both sides 7x>=16 7x on both sides That's what I'm doing but it isn't getting the right answer , I think! HELP!
 2 years ago
 2 years ago

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Hero Group TitleBest ResponseYou've already chosen the best response.1
–2(x – 3) ≥ 5 – (x + 3) 2x + 6 ≥ 5  x  3 2x + 6 ≥ 5  3  x 2x + 6 ≥ 2  x 6  2 ≥ 2x  x 4 ≥ x
 2 years ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
AH! Genius!! :D
 2 years ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
... wait... how did you get 2x + 6 ≥ 5  x  3 ??
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Distribute the negative
 2 years ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but don't you distribute 5 to x for 5x and then 5 to 3 to get 15?!?
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
No bro. Don't you see that my solution is correct?
 2 years ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, I do... guess I'm still a little confused though...
 2 years ago

gcuwagirl Group TitleBest ResponseYou've already chosen the best response.0
The 5 is not being multiplied with the (x+3); it is 5 + 1(x+3) which gives 5  x  3
 2 years ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
ahh... I got it now... thanks you guys!!! :D
 2 years ago
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