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AGummiBear55
Group Title
PLEASE HELP me solve the inequality: –2(x – 3) ≥ 5 – (x + 3) Here's my work so far: 2(x3)>=5(x3)
2x+6>=55x+15
2x+6>=5x10
6 on both sides
2x>=5x16
5x on both sides
7x>=16
7x on both sides
That's what I'm doing but it isn't getting the right answer , I think! HELP!
 one year ago
 one year ago
AGummiBear55 Group Title
PLEASE HELP me solve the inequality: –2(x – 3) ≥ 5 – (x + 3) Here's my work so far: 2(x3)>=5(x3) 2x+6>=55x+15 2x+6>=5x10 6 on both sides 2x>=5x16 5x on both sides 7x>=16 7x on both sides That's what I'm doing but it isn't getting the right answer , I think! HELP!
 one year ago
 one year ago

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Hero Group TitleBest ResponseYou've already chosen the best response.1
–2(x – 3) ≥ 5 – (x + 3) 2x + 6 ≥ 5  x  3 2x + 6 ≥ 5  3  x 2x + 6 ≥ 2  x 6  2 ≥ 2x  x 4 ≥ x
 one year ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
AH! Genius!! :D
 one year ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
... wait... how did you get 2x + 6 ≥ 5  x  3 ??
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Distribute the negative
 one year ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but don't you distribute 5 to x for 5x and then 5 to 3 to get 15?!?
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
No bro. Don't you see that my solution is correct?
 one year ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, I do... guess I'm still a little confused though...
 one year ago

gcuwagirl Group TitleBest ResponseYou've already chosen the best response.0
The 5 is not being multiplied with the (x+3); it is 5 + 1(x+3) which gives 5  x  3
 one year ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
ahh... I got it now... thanks you guys!!! :D
 one year ago
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