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–2(x – 3) ≥ 5 – (x + 3)
-2x + 6 ≥ 5 - x - 3
-2x + 6 ≥ 5 - 3 - x
-2x + 6 ≥ 2 - x
6 - 2 ≥ 2x - x
4 ≥ x

AH! Genius!! :D

... wait... how did you get -2x + 6 ≥ 5 - x - 3 ??

Distribute the negative

Yeah, but don't you distribute 5 to x for 5x and then 5 to 3 to get 15?!?

No bro. Don't you see that my solution is correct?

Yeah, I do... guess I'm still a little confused though...

The 5 is not being multiplied with the (x+3); it is 5 + -1(x+3) which gives 5 - x - 3

ahh... I got it now... thanks you guys!!! :D