A community for students.
Here's the question you clicked on:
 0 viewing
AGummiBear55
 3 years ago
PLEASE HELP me solve the inequality: –2(x – 3) ≥ 5 – (x + 3) Here's my work so far: 2(x3)>=5(x3)
2x+6>=55x+15
2x+6>=5x10
6 on both sides
2x>=5x16
5x on both sides
7x>=16
7x on both sides
That's what I'm doing but it isn't getting the right answer , I think! HELP!
AGummiBear55
 3 years ago
PLEASE HELP me solve the inequality: –2(x – 3) ≥ 5 – (x + 3) Here's my work so far: 2(x3)>=5(x3) 2x+6>=55x+15 2x+6>=5x10 6 on both sides 2x>=5x16 5x on both sides 7x>=16 7x on both sides That's what I'm doing but it isn't getting the right answer , I think! HELP!

This Question is Closed

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1–2(x – 3) ≥ 5 – (x + 3) 2x + 6 ≥ 5  x  3 2x + 6 ≥ 5  3  x 2x + 6 ≥ 2  x 6  2 ≥ 2x  x 4 ≥ x

AGummiBear55
 3 years ago
Best ResponseYou've already chosen the best response.0... wait... how did you get 2x + 6 ≥ 5  x  3 ??

AGummiBear55
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, but don't you distribute 5 to x for 5x and then 5 to 3 to get 15?!?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1No bro. Don't you see that my solution is correct?

AGummiBear55
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, I do... guess I'm still a little confused though...

gcuwagirl
 3 years ago
Best ResponseYou've already chosen the best response.0The 5 is not being multiplied with the (x+3); it is 5 + 1(x+3) which gives 5  x  3

AGummiBear55
 3 years ago
Best ResponseYou've already chosen the best response.0ahh... I got it now... thanks you guys!!! :D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.