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Ldaniel

  • 3 years ago

Find the solution of the initial value problem. (dy/dx) = 6x^2 + 6x ; y(2) = 14

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  1. NoelGreco
    • 3 years ago
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    Separate variables and integrate \[\int\limits_{ }^{ }dy=\int\limits_{ }^{ }(6x ^{2}+6x) dx\]

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