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determine whether the series converges: sum(k=1 -> infinity) [1/(1+lnk)]

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what the limit of lnk as k to inf?
even if the n'th term tends to 0, it doesn't say the series converges.
yeah, was thinking thru the convergence tests :)

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Other answers:

harmonic series as an example.
does 1+ln(x) drop faster than x tho?
might need to use a comparison test
yes, that's what i was thinking.. i got -- 1/(1+lnk) > 1/lnk and i don't know where to go from here or this is even right..
it's the other way around. 1/lnk > 1/(1+ lnk) so if you can determine whether 1/ln k converges, you can say /1(1+lnk) converges. but if 1/lnk diverges, you can't say anything about 1/(1+lnk)
just use 1/k as a comparison
would 1/k be less than 1/1+lnk ?
that's the point
great, thanks!! :)

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