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Swageraid32
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@tcarroll010 can you help me with 4 and 5 of this....
 2 years ago
 2 years ago
Swageraid32 Group Title
@tcarroll010 can you help me with 4 and 5 of this....
 2 years ago
 2 years ago

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Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
those are my last two please........... ;/
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
# 4 D = b^2  4ac D = (1)^2  4(0.05)(1) D = ???
 2 years ago

shyLove98 Group TitleBest ResponseYou've already chosen the best response.0
I'm sorry. I don't know any of this. I tried. I'm really really really sorry. :(((
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
if you have a the equation of a parabola in standard form: y= ax^2 + bx +c you match up the coefficients of your equation with a, b, and c then use those numbers for a, b, and c in the formula discriminant= b^2 4ac jim_t already did most of the work for you.
 2 years ago

Beautiful_Lier96 Group TitleBest ResponseYou've already chosen the best response.0
im confused
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
y= 0.05 x^2 + 1x + 1 is your equation
 2 years ago

evergirl Group TitleBest ResponseYou've already chosen the best response.0
I think phi has got you covered
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
hmmm....???
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
you mean that is how i do the quadratic part??
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
we are doing question 4. They want to know the discriminant (of your quadratic equation) I assume they mean the equation they give in question 1 To find the discriminant we first do step 1: first step: pattern match y= 0.05 x^2 + 1x + 1 y= a x^2 +b x + c what is a,b, and c?
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
i have that part i need number 5
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
what did you get for a, b and c
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
wait what?? like for the explanation part??
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
D = (1)^2  4(0.05)(1)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
I see you copied Jim's answer To find the discriminant we first do step 1: first step: pattern match y= 0.05 x^2 + 1x + 1 y= a x^2 +b x + c what is a,b, and c?
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
a=0.05 b=1x c=1
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
almost, b is just 1 (we only want the numbers. a= 0.05, b=1 , c=1 step 2: replace the letters a, b, and c in b^2  4ab with the numbers you just found (remember b^2 is short for b*b 4ab is short for 4*a*b * means multiply
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
1^24(0.05)(1)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
now what is 1^2 ? 1*1 = 1 4*0.05 is 0.2 0.2*1 is 0.2 so 1 .2 = 0.8 the discriminant is 0.8
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
ok i get that thanks for actually working with me and not giving just the answer :D
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
so could you assist me in #5 as well??
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
@phi ??
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
For 5, the quadratic formula is \[ x=\frac{−b±\sqrt{b^2−4ac}}{2a}\] notice that the stuff inside the square root is the "discriminant", which you already figured out is 0.8 you also know what a, b and c are. So replace the letters with numbers what do you get?
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
a=0.05, b=1, c=1 \[x=\frac{−1±\sqrt{1^2 4\times0.05\times1}}{2\times0.05}\]
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
@phi ?? like that??
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
I just noticed that the equation you have from question 1 should be y= 0.05x^2 x +1 notice that b is 1 (not +1) this changes your answers (gack!)
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
yea i know it is a typo the graph is wrong
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
if we use b= 1 we get \[x= \frac{1 ± \sqrt{0.8}}{0.1}= 10±\sqrt{80} = 10± 4\sqrt{5} \] you get two answers x= 10+4sqrt(5) and x= 104sqrt(5) these are where the graph crosses the xaxis
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
wait i am confused
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
the part like so i need to switch it to a 1?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
It's your call. The question says find the equation, from the graph. Did you find the equation from the graph? If so, you got it wrong?
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
o wow no i used the graph that was provided on the graph ;( that means i have to go back and do this all again :/
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
Q1 general equation is y=0.05 x^2 x +1 vertex form is 0.05(x10)^2  4
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
so that means its this? y= 0.05 x^2 1x + 1
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in Q2, the 10 become +10 so that means its this? y= 0.05 x^2 1x + 1 Yes
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in Q2, the domain are all valid x's in this case, inf to +infinity
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in Q2, the range is all y values. from the graph, you see y is always bigger than 4
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in Q3, your xintercepts should be positive
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in Q4, b is 1 not +1, but it won't change the discriminant calculation.
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
ok thanks for all that :D
 2 years ago

Swageraid32 Group TitleBest ResponseYou've already chosen the best response.1
i do need your help again though i mean how are you supposed to find the domain and range? @phi
 2 years ago
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