anonymous
  • anonymous
can anyone help me with this problem find vertex and equation, line of symmetry and graph the function. f(x)= 1/3 x^2
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
f(x)=\[\frac{ x ^{2} }{ 3 }\]
anonymous
  • anonymous
I might be reading it wrong I am sorry
anonymous
  • anonymous
the parabola or quadratic equation is f(x)=ax^2 +bx +c, vertex x=-b/2a if you have a formula of f(x)= 1/3 x^2+bx +c --> here b=0 and c=0 vertex x=-b/2a x=-0/2(1/3)=0 sub this to f(x)= y=1/3 x^2=0 then what is the vertex V(x,y)=___? is it V(0,0) yes or no? for graphing use values of x=0,+-1,+-2 +-3 etc..etc....:D good luck now

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anonymous
  • anonymous
You had it right I think I was confused, but you really helped me understand the question...
anonymous
  • anonymous
ok good,,, good luck now and have fun ....:D
anonymous
  • anonymous
I will once someone looks at my problems lol..... One person is looking I just want to ensure I am on the right track....
anonymous
  • anonymous
ok where is the prob? i may be able to help a little bit :D
anonymous
  • anonymous
How would I show you?
anonymous
  • anonymous
If anyone can help me check my work I would be very thankful. So it can be more understandable I attached my work in a word file. Thank you so very much I just want to ensure I am on the right track.
anonymous
  • anonymous
Thats the question
anonymous
  • anonymous
hmm go to your prob site and notify my name there then i will click it and be there :D
anonymous
  • anonymous
like this hi andjie
anonymous
  • anonymous
I say your name
anonymous
  • anonymous
yes copy and paste my name there then ill just click on it
anonymous
  • anonymous
ok I did that
anonymous
  • anonymous
hmm i didnt have a notification,, did you highlight and copy then paste my name there?
anonymous
  • anonymous
Paste it where exactly lol
anonymous
  • anonymous
in the type your reply area, because I did that
anonymous
  • anonymous
on where you posted your problem
anonymous
  • anonymous
ok go back to where you posted your problem then paste my name there
anonymous
  • anonymous
I posted your name in the question
anonymous
  • anonymous
So confusing
anonymous
  • anonymous
hmm i dont know why i didnt get a notification?
anonymous
  • anonymous
is it still open? why dont you close it hen repost them new
anonymous
  • anonymous
ok

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