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Hope99

  • 3 years ago

Solving trigonometric equations! Help!

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  1. Hope99
    • 3 years ago
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    How did 3(1-cos^2x)+cos^2x = 2 Became: 3 - 2cos^2x=2 ?! Could you guys help me with this one!

  2. Hope99
    • 3 years ago
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    Why didnt we multiple 3 by (1 - cos^2x) as a whole? Thanks!

  3. campbell_st
    • 3 years ago
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    you need to solve for x so start with \[1 - \cos^2(x) = \sin^2(x) \] and substituting will give \[3\sin^2(x) + \cos^2(x) = 2\] or \[2 \sin^2(x) + \sin^2(x) + \cos^2(x) = 1\] and \[\sin^2(x) + \cos^2(x) = 1\] so you have \[2 \sin^2(x) + 1 = 2\] or \[2\sin^2(x) = 1\] you should be able to solve for x now in my solution I've tried to show every step so you can follow it... there are quicker solutions...

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