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Hope99 Group TitleBest ResponseYou've already chosen the best response.0
How did 3(1cos^2x)+cos^2x = 2 Became: 3  2cos^2x=2 ?! Could you guys help me with this one!
 one year ago

Hope99 Group TitleBest ResponseYou've already chosen the best response.0
Why didnt we multiple 3 by (1  cos^2x) as a whole? Thanks!
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
you need to solve for x so start with \[1  \cos^2(x) = \sin^2(x) \] and substituting will give \[3\sin^2(x) + \cos^2(x) = 2\] or \[2 \sin^2(x) + \sin^2(x) + \cos^2(x) = 1\] and \[\sin^2(x) + \cos^2(x) = 1\] so you have \[2 \sin^2(x) + 1 = 2\] or \[2\sin^2(x) = 1\] you should be able to solve for x now in my solution I've tried to show every step so you can follow it... there are quicker solutions...
 one year ago
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