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soccergal12
show that equation: a = V^2_(av) / R is dimensionally correct. i.e. show that the units match on both sides of the equation
[a]=L.T^-2 [v]=L.T^-1 [R]=L Hence [v^2/R]=[v]^2/[R]=L^2.T^-2/L=L.T^-2=[a]
where L=''unit of length'', T=''unit of time''
and [x]=''dimensions of x''