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mgjimenez1
Group Title
A 600kg car is going over a curve with a radius of 120 meters that is banked at an angle of 25 degrees with a speed of 30 meters per second. The coefficient of static friction between the car and the road is 0.3. What is the normal force exerted by the road on the car? a) 7240 N b) 1590 N c) 5330 N d) 3430 N e) 3620 N
 one year ago
 one year ago
mgjimenez1 Group Title
A 600kg car is going over a curve with a radius of 120 meters that is banked at an angle of 25 degrees with a speed of 30 meters per second. The coefficient of static friction between the car and the road is 0.3. What is the normal force exerted by the road on the car? a) 7240 N b) 1590 N c) 5330 N d) 3430 N e) 3620 N
 one year ago
 one year ago

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VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
First thing to do is draw a freebody diagram of the situation.
 one year ago

jufetluz Group TitleBest ResponseYou've already chosen the best response.0
you can use the formula tan (theta) = v²/gR where theta is your angle, v is your velocity, g the acceleration due to gravity and R your radius
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
This formula will give you the velocity for which friction is zero, but it will not provide an answer to the question.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Ny=P=mg;
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
What´s is the value for G force?
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Try to use the Diagram for solve the problem.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Here is the answer.
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.0
Here is the solution:
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
@Dikawar You went right, but it is even easier to project along the normal of the road:  only one projection needed  no system to solve for N, as f does not appear in the equation.
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
@Dikawar Have a look at the solution I wrote here (you'll have to scroll down to the one with the drawing): http://openstudy.com/study?version=feed:joinstudygroup&referrer=mit%208.01%20physics%20i%20classical%20mechanics,%20fall%201999&domain=ocw.mit.edu#/updates/50bc2ea4e4b0bcefefa06b4d
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
*sorry @Diwakar
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr Thanks! Your method is much better and easier .
 one year ago
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