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mgjimenez1 Group Title

A 600-kg car is going over a curve with a radius of 120 meters that is banked at an angle of 25 degrees with a speed of 30 meters per second. The coefficient of static friction between the car and the road is 0.3. What is the normal force exerted by the road on the car? a) 7240 N b) 1590 N c) 5330 N d) 3430 N e) 3620 N

  • one year ago
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  1. Vincent-Lyon.Fr Group Title
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    First thing to do is draw a free-body diagram of the situation.

    • one year ago
  2. jufetluz Group Title
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    you can use the formula tan (theta) = v²/gR where theta is your angle, v is your velocity, g the acceleration due to gravity and R your radius

    • one year ago
  3. Vincent-Lyon.Fr Group Title
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    This formula will give you the velocity for which friction is zero, but it will not provide an answer to the question.

    • one year ago
  4. viniterranova Group Title
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    Ny=P=mg;

    • one year ago
  5. viniterranova Group Title
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    What´s is the value for G force?

    • one year ago
  6. viniterranova Group Title
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    Try to use the Diagram for solve the problem.

    • one year ago
  7. viniterranova Group Title
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    Here is the answer.

    • one year ago
  8. Diwakar Group Title
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    Here is the solution:

    • one year ago
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  9. Vincent-Lyon.Fr Group Title
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    @Dikawar You went right, but it is even easier to project along the normal of the road: - only one projection needed - no system to solve for N, as f does not appear in the equation.

    • one year ago
  10. Vincent-Lyon.Fr Group Title
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    @Dikawar Have a look at the solution I wrote here (you'll have to scroll down to the one with the drawing): http://openstudy.com/study?version=feed:join-study-group&referrer=mit%208.01%20physics%20i%20classical%20mechanics,%20fall%201999&domain=ocw.mit.edu#/updates/50bc2ea4e4b0bcefefa06b4d

    • one year ago
  11. Vincent-Lyon.Fr Group Title
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    *sorry @Diwakar

    • one year ago
  12. Diwakar Group Title
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    @Vincent-Lyon.Fr Thanks! Your method is much better and easier .

    • one year ago
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