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 2 years ago
During an diffusion experiment, it took 75 seconds for a certain number of moles of an unknown gas
to pass through a tiny hole. Under the same conditions, the same number of moles of oxygen gas
passed through the hole in 30 seconds. What is the molar mass of the unknown gas?
 2 years ago
During an diffusion experiment, it took 75 seconds for a certain number of moles of an unknown gas to pass through a tiny hole. Under the same conditions, the same number of moles of oxygen gas passed through the hole in 30 seconds. What is the molar mass of the unknown gas?

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JFraser
 2 years ago
Best ResponseYou've already chosen the best response.0In general, the heavier a gas molecule is, the slower it moves, and the longer it takes to effuse (escape through a tiny hole in a barrier). Graham's Law describes the relationship between the molar mass of a gas and its relative rate of effusion.\[\frac {R_1}{R_2} = \sqrt{\frac{MM_2}{MM_1}}\] You know that gas 1 passed through the hole in 75 seconds, and that gas 2 took only 30 seconds. You also know that gas 2 is oxygen gas \O_2. Oxygen gas has a molar mass of 32g/mol. The only thing missing is MM1. Plug and solve
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