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Write each arithmetic series as the sum of terms, find each sum.

Mathematics
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|dw:1354171632278:dw|
is the answer 20?
it similar by : 3(1) + 3(2) + 3(3) + 3(4) + ... + 3(10) = 3(1+2+3+4+...+10) = ......

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Other answers:

so im wrong, i thought you were supposed to use the formula, Sn=n(a1+an)/2
That wording is a bit interesting. Are there multiple questions like this to find the answer for, or just this one?
yea there are about 8 questions that are under that two part question
Your formula would work; you must have done it wrong.
\[S_{n} = \frac{n}{2} (a_{1} + a_{n})\] Did you use 10 for \(n\) and 3 for \(a_{1}\)?
for : n=1 ----> 3(1) = 3 n=2 ----> 3(2) = 6 n=3 ----> 3(3) = 9 .... so on, the series be 3+6+9+....+30 yes, use the formula like @geoffb said :)
for n, i put 10, a1, i put 1, and for A n, i put 3
Okay, that's the problem. \(a_{1}\) means the value of your first term (which is 3 times 1, or 3). \(a_{n}\) means the value of your n-th term. In this case, n is 10, so the value of the 10th term is 3 times 10, or 30.
i got 75, am i right?
No. What is your calculation?
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Why are you using 10 for \(a_{n}\)?
It wants \(a_{n}\), not \(n\).
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That looks great.
ughhh finally!
so i get 330/2=165
Yup. :)

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