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RadEnBest ResponseYou've already chosen the best response.1
it similar by : 3(1) + 3(2) + 3(3) + 3(4) + ... + 3(10) = 3(1+2+3+4+...+10) = ......
 one year ago

LifeBest ResponseYou've already chosen the best response.0
so im wrong, i thought you were supposed to use the formula, Sn=n(a1+an)/2
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
That wording is a bit interesting. Are there multiple questions like this to find the answer for, or just this one?
 one year ago

LifeBest ResponseYou've already chosen the best response.0
yea there are about 8 questions that are under that two part question
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
Your formula would work; you must have done it wrong.
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
\[S_{n} = \frac{n}{2} (a_{1} + a_{n})\] Did you use 10 for \(n\) and 3 for \(a_{1}\)?
 one year ago

RadEnBest ResponseYou've already chosen the best response.1
for : n=1 > 3(1) = 3 n=2 > 3(2) = 6 n=3 > 3(3) = 9 .... so on, the series be 3+6+9+....+30 yes, use the formula like @geoffb said :)
 one year ago

LifeBest ResponseYou've already chosen the best response.0
for n, i put 10, a1, i put 1, and for A n, i put 3
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
Okay, that's the problem. \(a_{1}\) means the value of your first term (which is 3 times 1, or 3). \(a_{n}\) means the value of your nth term. In this case, n is 10, so the value of the 10th term is 3 times 10, or 30.
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
No. What is your calculation?
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
Why are you using 10 for \(a_{n}\)?
 one year ago

geoffbBest ResponseYou've already chosen the best response.1
It wants \(a_{n}\), not \(n\).
 one year ago
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