Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I honestly don't understand how to solve linear word problems... Can someone help me solve one?

Linear Algebra
I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

I honestly don't understand how to solve linear word problems.. Here's the quesion: 1a. ) The Peanut gallery made a profit of $16,450 in 2002, and a profit of $21,340 in 2005. Assume that the profit followed a linear pattern. Write an equation that gives the profit, y, in terms of the year, x. Let x=0 correspond to 2000. Equation: 1b.) What was the profit in 2008 1c.) In what year would the profit be $31, 120 in the trend continued? Please show explanations & work. I really..don't understand this. (I obviously know the basics- solving equations, finding slope from an equation, y=mx + b, etc.)
ok, so you know the generic linear equation y=mx+b, and you also know that y=profit, x = year (where x=0 corresponds to year 2000), also, you are given enough data to set up two linear equation of the form y=mx+b. can you try to set up two equations?
if you need farther help, ask :D

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Um..I don't know..
You're supposed to find one equation of this problem. That can be done, by using more than one equations I think..
alright, so in the year 2002 (x=2), the profit is y = 16450, then that means: A: 16450 = 2m + b can you set up equation B?
Equation "B" as in finding the slope?
i mean another linear equation which i denote as "B", similar to equation "A" that I've set up above
Okay. I need clarification. My Algebra teacher solved this problem like this: |dw:1354175590461:dw|
Can you explain what she (teacher) did there?
the equation is correct. what your teacher did is solve a system of two linear equations, which are the equations A which as shown earlier, and equation B, which has a very similar setup as A. to match what your teacher did, let A and B be two linear equations as shown below: A: y = mx + b B: Y = mX + b then, to solve for m: m = (Y-y)/(X-x)
after solving for m, plug m back into either A or B to solve for b, and you get your equation :D
What is equation "A" & "B"?
equation "A" was shown earlier, remember? and "B" has a similar set up using the data given
"alright, so in the year 2002 (x=2), the profit is y = 16450, then that means: A: 16450 = 2m + b can you set up equation B?"
Oh. Yeah. Of course. Could you solve 1b for me?
i can help you on 1b, but can you show me your 1a first :D
Okay. y = 1630(2002) +13190
^ is B
for B the year would be 2005, so x = ?
2002 is for A, which makes x = 2, what about B?
Yeah..I think I did something wrong with this equation
remember, x=0 mean 2000, that means x=1 is 2001, x=2 is 2002, x=3 is 2003 and so on
y = 1630(8) + 13190
thats for 1b, which means y = ?
y= 13040 + 13190 y = 26230
26230 = profit.
yep you got it :D
Where did '5- 2" from the upper equation used to solve 1a come from?
that is from "X-x", where X = 5 for 2005, and x = 2 for 2002
Why did they need to be subtracted from each other?
Why did "5-2" have to happen? Why is that relevant?
What is B - A?
What is equation B minus equation A?
2005 - 2002? --> Used 5 from 2005, and "2" from 2002?
I don't know. That's why I'm asking you.
What is equation A and equation B? you should know this by now.
but, if you just want to understand the X-x part, then you have to understand what the slope m of an linear equation means
it means the rate of change of y with respect to x
Yes I know. But..
I'm very frustrated. I was just wondering if you could solve the equation, (and just the equation) and give me step-by-step explanations.
Your teaching methods..aren't helping me...that much. No offense.......
To solve for the slope m, just compute m = (Y-y)/(X-x) where Y and X are from one linear equation, while y and x are from the other. then substitute m back into anyone of those two equations, to solve for b, and you get the equation that you want.
which is y = mx + b, where m and b are the value found using the above method.

Not the answer you are looking for?

Search for more explanations.

Ask your own question