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\[y_c = e^{-4x} (Acos(2x) + Bsin(2x))\]

Oh.. undetermined coefficient.. not variation of parameters. :\

But when we expand sin2x, we get 2sinxcosx..

|dw:1354198038401:dw|

Oh yeah, so you can use it on e^x.

Yes!

Am I answering your question, or just rambling about stuff you already know?

Hmm... My question is basically why we don't need the x for yp.. :\

Well x is implicitly in a cos x + b sin x. Not sure if that's what you mean.

I don't really understand what you mean.

Would you mind explaining why it is linearly independent...?

Hmm... I guess I have to try more question to see if I get your point.. Thanks for your help!!

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