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imnotblack

  • 3 years ago

PreCalculus graphing problem http://prntscr.com/kvsts

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  1. geerky42
    • 3 years ago
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    What don't you understand?

  2. zordoloom
    • 3 years ago
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    Do you have a graphing calculator?

  3. imnotblack
    • 3 years ago
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    I'm terrible at math, and no I do not.

  4. geerky42
    • 3 years ago
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    Do you know what parent function (y = x²) looks like?

  5. imnotblack
    • 3 years ago
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    Nope. >.<

  6. imnotblack
    • 3 years ago
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    Can you help me?

  7. cwrw238
    • 3 years ago
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    |dw:1354197324629:dw|

  8. cwrw238
    • 3 years ago
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    thats the graph of y = x^2 (very roughly - lol!)

  9. imnotblack
    • 3 years ago
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    What does that have to do with the question?

  10. cwrw238
    • 3 years ago
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    we can transform y = x^2 to the graph on your diagram by 2 trasformations first reflecting it in the axis gives y = -x^2 |dw:1354197562913:dw|

  11. cwrw238
    • 3 years ago
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    then adding 1 to the function moves the whole graph 1 unit up the y-axis so can you see which option is correct graph?

  12. imnotblack
    • 3 years ago
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    is it A. j(x) = -x2 + 1? I'm horrid at math. >.<

  13. cwrw238
    • 3 years ago
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    yes thats right

  14. imnotblack
    • 3 years ago
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    Thank you. :)

  15. cwrw238
    • 3 years ago
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    yw

  16. imnotblack
    • 3 years ago
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    x varies inversely as v, and x = 48 when v = 8. Find x when v = 64. A. x = 6 B. x = 64 C. x = 8 D. x = 48 It's 6 right?

  17. cwrw238
    • 3 years ago
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    yes

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