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HELP! PLEASE! When a crew rows with the current, it travels 16 miles in 2 hours. Against the current, the crew rows 8 miles in 2 hours. Let x= the crew's rowing rate in still water and let y= the rate of the current. (Solve with Calcculator) What is the input? What is the output? What is the rate of rowing? What is the rate of current?

Linear Algebra
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allright, il set it up for ya and see if ya can figure it out! Rate x Time = Distance... so im gonna go to the drawing board now!
|dw:1354314486582:dw| so x=6... now plug x back into the equation so (next drawing)
|dw:1354314768442:dw| and that is that! u shud b able to finish the rest yourself!

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