Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Ruchi.
Group Title
Q. the graph relates In K vs 1/T for a reaction .the reaction must be :
 2 years ago
 2 years ago
Ruchi. Group Title
Q. the graph relates In K vs 1/T for a reaction .the reaction must be :
 2 years ago
 2 years ago

This Question is Closed

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
dw:1354201232478:dw A) exothermic B) endothermic
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
which option is correct?
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
can u hlp me out .plzzz
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.0
i am really sorry. I have no idea
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
can u suggest any one on os to hlp me @ajprincess
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.0
I am nt sure. i rarely visit chemistry group. So have no idea. Am really sorry.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
listen from the graph we find out the how K depends on temperature now we know that on increasing temp favourable for endothermic but here K i increasing on decreasing temp means it exothermic
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
might u read some law like on increasing temp exothermic show backward reaction while endothermic show forward reaction
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
temp is also increasing
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
no its not see 1/T
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
i'm nt understanding the graph ?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
do u know wat is k?
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
euilibrium constant?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
yes and will u give me the formula of kc
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
that is kc=concn of product/concn of react
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
ok now here in graph K is increasing on increasing the value of 1/T means temp i decreasing and on deacresing temp and K also increasing then it must be a exothermic process
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
in starting its temp. is 1.5 ,2,2.5 so its increasing
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
dear its not T u are provided 1/T
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
1/T means if the values are given are in increasing order den T is decreasing but if its value of T given in increassing order then T i increasing
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
decreasing then increasing
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.0
see whther they written T or 1/T or ask ur teach dey will explain u the difference abu T and 1/T
 2 years ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
i hav understood it wait i'm posting 2nd question.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.