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variation of log K with 1/T is shown by the following graph .delta H for the reaction will be:

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same reason as for previous qn

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Other answers:

a) -19.14 jmol^-1 b)+19.14 J mol^-1 c)+4.606 cal mol^-1 d)-2cal mol^-1
correct answer is which one & why?
why or how?
i dont remeber how but i read this value before and yea main ans will be in -ve
why its in negative?
then it -2 also?
welll it cant be d as 19.14 is uiveral value of something unable to recall srry
well negative coz og exothermic process give me a sec i ll show u the proof ok let me chck my notes
ni mil rha sorry
okay i will get it i hav to ask u one thing that delta H unit is joule ?

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