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growdabone
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whaddya need done? solving for "x" or something else?
mew55
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i believe u have to use the quadratic formula
mew55
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i am getting -154 under the square root :/
mew55
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but this is +3, where is the 3?
the only way to get the 3 is 5-8
mew55
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sorry 8-5
ChristianGeek
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Oops, my bad! Let me rewrite.
mew55
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I believe this is a quadratic formula problem but the inside of the square root gave me
Rell25
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Find the product of the solution of this equation
mew55
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|dw:1354209002036:dw|
mew55
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|dw:1354209128299:dw|
Rell25
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\[5x^2+3x+8=0\]
ChristianGeek
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Sorry, I was not paying attention in my deleted response (see how easy it is to go too quickly and get it wrong?!). @mew55 is correct...you do need the quadratic formula:
\[x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} = \frac{-3 \pm \sqrt{3^{2} - 4(5)(8)}}{2(5)} = \frac{-3 \pm \sqrt{9 - 160}}{10} = \frac{-3 \pm \sqrt{151}}{10}\]
151 is a prime number, so you can't simplify any more than that without a calculator.
mew55
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does the 'i' needs to be simplify since the inside of the square root is -151?
mew55
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and its okay XD
ChristianGeek
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Forgot the negative in the final square root...should be:
\[\frac{-3 \pm \sqrt{-151}}{10}\]
ChristianGeek
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@mew55...you could:
\[\frac{-3 \pm \sqrt{151}(i)}{10}\]
mew55
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yep. that is wut i was thinking. XD X3