anonymous
  • anonymous
5x^2+3x+8=0
Precalculus
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
whaddya need done? solving for "x" or something else?
mew55
  • mew55
i believe u have to use the quadratic formula
mew55
  • mew55
i am getting -154 under the square root :/

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mew55
  • mew55
but this is +3, where is the 3? the only way to get the 3 is 5-8
mew55
  • mew55
sorry 8-5
anonymous
  • anonymous
Oops, my bad! Let me rewrite.
mew55
  • mew55
I believe this is a quadratic formula problem but the inside of the square root gave me
anonymous
  • anonymous
Find the product of the solution of this equation
mew55
  • mew55
|dw:1354209002036:dw|
mew55
  • mew55
|dw:1354209128299:dw|
anonymous
  • anonymous
\[5x^2+3x+8=0\]
anonymous
  • anonymous
Sorry, I was not paying attention in my deleted response (see how easy it is to go too quickly and get it wrong?!). @mew55 is correct...you do need the quadratic formula: \[x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} = \frac{-3 \pm \sqrt{3^{2} - 4(5)(8)}}{2(5)} = \frac{-3 \pm \sqrt{9 - 160}}{10} = \frac{-3 \pm \sqrt{151}}{10}\] 151 is a prime number, so you can't simplify any more than that without a calculator.
mew55
  • mew55
does the 'i' needs to be simplify since the inside of the square root is -151?
mew55
  • mew55
and its okay XD
anonymous
  • anonymous
Forgot the negative in the final square root...should be: \[\frac{-3 \pm \sqrt{-151}}{10}\]
anonymous
  • anonymous
@mew55...you could: \[\frac{-3 \pm \sqrt{151}(i)}{10}\]
mew55
  • mew55
yep. that is wut i was thinking. XD X3

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