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growdabone
 2 years ago
Best ResponseYou've already chosen the best response.0whaddya need done? solving for "x" or something else?

mew55
 2 years ago
Best ResponseYou've already chosen the best response.0i believe u have to use the quadratic formula

mew55
 2 years ago
Best ResponseYou've already chosen the best response.0i am getting 154 under the square root :/

mew55
 2 years ago
Best ResponseYou've already chosen the best response.0but this is +3, where is the 3? the only way to get the 3 is 58

ChristianGeek
 2 years ago
Best ResponseYou've already chosen the best response.0Oops, my bad! Let me rewrite.

mew55
 2 years ago
Best ResponseYou've already chosen the best response.0I believe this is a quadratic formula problem but the inside of the square root gave me

Rell25
 2 years ago
Best ResponseYou've already chosen the best response.0Find the product of the solution of this equation

ChristianGeek
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry, I was not paying attention in my deleted response (see how easy it is to go too quickly and get it wrong?!). @mew55 is correct...you do need the quadratic formula: \[x = \frac{b \pm \sqrt{b^{2}  4ac}}{2a} = \frac{3 \pm \sqrt{3^{2}  4(5)(8)}}{2(5)} = \frac{3 \pm \sqrt{9  160}}{10} = \frac{3 \pm \sqrt{151}}{10}\] 151 is a prime number, so you can't simplify any more than that without a calculator.

mew55
 2 years ago
Best ResponseYou've already chosen the best response.0does the 'i' needs to be simplify since the inside of the square root is 151?

ChristianGeek
 2 years ago
Best ResponseYou've already chosen the best response.0Forgot the negative in the final square root...should be: \[\frac{3 \pm \sqrt{151}}{10}\]

ChristianGeek
 2 years ago
Best ResponseYou've already chosen the best response.0@mew55...you could: \[\frac{3 \pm \sqrt{151}(i)}{10}\]

mew55
 2 years ago
Best ResponseYou've already chosen the best response.0yep. that is wut i was thinking. XD X3
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