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growdabone Group TitleBest ResponseYou've already chosen the best response.0
whaddya need done? solving for "x" or something else?
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
i believe u have to use the quadratic formula
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
i am getting 154 under the square root :/
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
but this is +3, where is the 3? the only way to get the 3 is 58
 one year ago

ChristianGeek Group TitleBest ResponseYou've already chosen the best response.0
Oops, my bad! Let me rewrite.
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
I believe this is a quadratic formula problem but the inside of the square root gave me
 one year ago

Rell25 Group TitleBest ResponseYou've already chosen the best response.0
Find the product of the solution of this equation
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
dw:1354209002036:dw
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
dw:1354209128299:dw
 one year ago

Rell25 Group TitleBest ResponseYou've already chosen the best response.0
\[5x^2+3x+8=0\]
 one year ago

ChristianGeek Group TitleBest ResponseYou've already chosen the best response.0
Sorry, I was not paying attention in my deleted response (see how easy it is to go too quickly and get it wrong?!). @mew55 is correct...you do need the quadratic formula: \[x = \frac{b \pm \sqrt{b^{2}  4ac}}{2a} = \frac{3 \pm \sqrt{3^{2}  4(5)(8)}}{2(5)} = \frac{3 \pm \sqrt{9  160}}{10} = \frac{3 \pm \sqrt{151}}{10}\] 151 is a prime number, so you can't simplify any more than that without a calculator.
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
does the 'i' needs to be simplify since the inside of the square root is 151?
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
and its okay XD
 one year ago

ChristianGeek Group TitleBest ResponseYou've already chosen the best response.0
Forgot the negative in the final square root...should be: \[\frac{3 \pm \sqrt{151}}{10}\]
 one year ago

ChristianGeek Group TitleBest ResponseYou've already chosen the best response.0
@mew55...you could: \[\frac{3 \pm \sqrt{151}(i)}{10}\]
 one year ago

mew55 Group TitleBest ResponseYou've already chosen the best response.0
yep. that is wut i was thinking. XD X3
 one year ago
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