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Rell25

  • 2 years ago

5x^2+3x+8=0

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  1. growdabone
    • 2 years ago
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    whaddya need done? solving for "x" or something else?

  2. mew55
    • 2 years ago
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    i believe u have to use the quadratic formula

  3. mew55
    • 2 years ago
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    i am getting -154 under the square root :/

  4. mew55
    • 2 years ago
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    but this is +3, where is the 3? the only way to get the 3 is 5-8

  5. mew55
    • 2 years ago
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    sorry 8-5

  6. ChristianGeek
    • 2 years ago
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    Oops, my bad! Let me rewrite.

  7. mew55
    • 2 years ago
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    I believe this is a quadratic formula problem but the inside of the square root gave me

  8. Rell25
    • 2 years ago
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    Find the product of the solution of this equation

  9. mew55
    • 2 years ago
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    |dw:1354209002036:dw|

  10. mew55
    • 2 years ago
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    |dw:1354209128299:dw|

  11. Rell25
    • 2 years ago
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    \[5x^2+3x+8=0\]

  12. ChristianGeek
    • 2 years ago
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    Sorry, I was not paying attention in my deleted response (see how easy it is to go too quickly and get it wrong?!). @mew55 is correct...you do need the quadratic formula: \[x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} = \frac{-3 \pm \sqrt{3^{2} - 4(5)(8)}}{2(5)} = \frac{-3 \pm \sqrt{9 - 160}}{10} = \frac{-3 \pm \sqrt{151}}{10}\] 151 is a prime number, so you can't simplify any more than that without a calculator.

  13. mew55
    • 2 years ago
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    does the 'i' needs to be simplify since the inside of the square root is -151?

  14. mew55
    • 2 years ago
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    and its okay XD

  15. ChristianGeek
    • 2 years ago
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    Forgot the negative in the final square root...should be: \[\frac{-3 \pm \sqrt{-151}}{10}\]

  16. ChristianGeek
    • 2 years ago
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    @mew55...you could: \[\frac{-3 \pm \sqrt{151}(i)}{10}\]

  17. mew55
    • 2 years ago
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    yep. that is wut i was thinking. XD X3

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