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Carniel Group Title

John is lifting a 1.5 kg toy to a height of 1.2 m above the ground. How much work is done??

  • one year ago
  • one year ago

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  1. adnanchowdhury Group Title
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    This question should have been asked in the physics sections but I'll still provide you an answer. Work done (Joules) = Force (N) x Distance (m) The only force that we know of that is acting on the toy (ignoring resistive forces) is the weight and tension of the string lifting the object. Weight = mass x acceleration due to gravity = mg. The tension is the force that is causing the work to be done and is equal to the weight. So tension = mg. Work Done = Tension x distance. = 1.5 x 9.8 x 1.2 |dw:1354221984926:dw|

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