anonymous
  • anonymous
-2p^2-6p+20 Can someone help me factor this problem.? Im so confused.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
-2-10p+4p+20
anonymous
  • anonymous
-2(p+5)(p-2)
anonymous
  • anonymous
-2p^2+4p-10p+20

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anonymous
  • anonymous
Factor the two out... -2(p^2 + 3p +10) Now you can see that (p^2 + 3p +10) becomes (p+5)(p-2)
anonymous
  • anonymous
Thanks LogicalReason that helped alot.
anonymous
  • anonymous
-2p(p-2)-10(p-2) (-2p-10)(p-2) -2(p+5)(p-2)
anonymous
  • anonymous
If you're confused on how to solve these (look at LogicalReason's reply before this). Multiply the term before p^2, in this case 1, with the term with no x, in this case 10. Then find two factors of 10 that add up to 3. In this case, that's 5 and -2. Those two numbers become the two numbers in the new equation below: -2(p+5)(p-2)
anonymous
  • anonymous
Sorry, I had a typo. The two numbers you multiply are actually 1 and -10, so you need to find the two factors that multiply into -10, that when added together equal three. Logical's reply had (p^2 + 3p +10) when it should have been (p^2 + 3p -10). The factors are still 5 and -2, though. Just read the above comment, but replace 10 with -10 and it'll make more sense.

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