Here's the question you clicked on:
Sunshine447
Can someone please help me with this? The lesson explains it, but I just don't get it..... Jerry inscribed a quadrilateral ABCD in a circle, as shown below. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0800_Subtest_01_06/image0024e67730b.jpg If the measure of arc BCD is 250°, what is the measure of angle BCD?
cant link directly to flvs
It's from the lesson...
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notice that the angle at c ison the edge of the circle; there is a property that says this angle is half the arc across from it
where does the 250 come from?
BCD = 250 is stated in the question ....
The inscribed quadrilateral theorem?
i got no idea what its spose to be called :)
I got 10 and 5 when I solved the part you wrote....... @amistre64
360-250 is the arc that angle BCD is facing soo; BCD = (360-250)/2 = 110/2 = 55 to me
ohhhhhhhhhhhhhhhhhhhh okay, so it's 55 because it's half of the opposite arc?