anonymous
  • anonymous
Can someone please help me with this? The lesson explains it, but I just don't get it..... Jerry inscribed a quadrilateral ABCD in a circle, as shown below. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0800_Subtest_01_06/image0024e67730b.jpg If the measure of arc BCD is 250°, what is the measure of angle BCD?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
@amistre64 @phi
amistre64
  • amistre64
cant link directly to flvs
anonymous
  • anonymous
It's from the lesson...

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amistre64
  • amistre64
|dw:1354227203795:dw|
amistre64
  • amistre64
notice that the angle at c ison the edge of the circle; there is a property that says this angle is half the arc across from it
anonymous
  • anonymous
where does the 250 come from?
amistre64
  • amistre64
BCD = 250 is stated in the question ....
anonymous
  • anonymous
The inscribed quadrilateral theorem?
anonymous
  • anonymous
okay
amistre64
  • amistre64
i got no idea what its spose to be called :)
anonymous
  • anonymous
okay haha
anonymous
  • anonymous
I got 10 and 5 when I solved the part you wrote....... @amistre64
amistre64
  • amistre64
360-250 is the arc that angle BCD is facing soo; BCD = (360-250)/2 = 110/2 = 55 to me
anonymous
  • anonymous
ohhhhhhhhhhhhhhhhhhhh okay, so it's 55 because it's half of the opposite arc?

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