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Sunshine447 Group Title

Can someone please help me with this? The lesson explains it, but I just don't get it..... Jerry inscribed a quadrilateral ABCD in a circle, as shown below. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0800_Subtest_01_06/image0024e67730b.jpg If the measure of arc BCD is 250°, what is the measure of angle BCD?

  • one year ago
  • one year ago

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  1. Sunshine447 Group Title
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    @amistre64 @phi

    • one year ago
  2. amistre64 Group Title
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    cant link directly to flvs

    • one year ago
  3. Sunshine447 Group Title
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    It's from the lesson...

    • one year ago
  4. amistre64 Group Title
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    |dw:1354227203795:dw|

    • one year ago
  5. amistre64 Group Title
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    notice that the angle at c ison the edge of the circle; there is a property that says this angle is half the arc across from it

    • one year ago
  6. Sunshine447 Group Title
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    where does the 250 come from?

    • one year ago
  7. amistre64 Group Title
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    BCD = 250 is stated in the question ....

    • one year ago
  8. Sunshine447 Group Title
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    The inscribed quadrilateral theorem?

    • one year ago
  9. Sunshine447 Group Title
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    okay

    • one year ago
  10. amistre64 Group Title
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    i got no idea what its spose to be called :)

    • one year ago
  11. Sunshine447 Group Title
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    okay haha

    • one year ago
  12. Sunshine447 Group Title
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    I got 10 and 5 when I solved the part you wrote....... @amistre64

    • one year ago
  13. amistre64 Group Title
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    360-250 is the arc that angle BCD is facing soo; BCD = (360-250)/2 = 110/2 = 55 to me

    • one year ago
  14. Sunshine447 Group Title
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    ohhhhhhhhhhhhhhhhhhhh okay, so it's 55 because it's half of the opposite arc?

    • one year ago
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