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Sunshine447

  • 3 years ago

Can someone please help me with this? The lesson explains it, but I just don't get it..... Jerry inscribed a quadrilateral ABCD in a circle, as shown below. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0800_Subtest_01_06/image0024e67730b.jpg If the measure of arc BCD is 250°, what is the measure of angle BCD?

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  1. Sunshine447
    • 3 years ago
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    @amistre64 @phi

  2. amistre64
    • 3 years ago
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    cant link directly to flvs

  3. Sunshine447
    • 3 years ago
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    It's from the lesson...

  4. amistre64
    • 3 years ago
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    |dw:1354227203795:dw|

  5. amistre64
    • 3 years ago
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    notice that the angle at c ison the edge of the circle; there is a property that says this angle is half the arc across from it

  6. Sunshine447
    • 3 years ago
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    where does the 250 come from?

  7. amistre64
    • 3 years ago
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    BCD = 250 is stated in the question ....

  8. Sunshine447
    • 3 years ago
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    The inscribed quadrilateral theorem?

  9. Sunshine447
    • 3 years ago
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    okay

  10. amistre64
    • 3 years ago
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    i got no idea what its spose to be called :)

  11. Sunshine447
    • 3 years ago
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    okay haha

  12. Sunshine447
    • 3 years ago
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    I got 10 and 5 when I solved the part you wrote....... @amistre64

  13. amistre64
    • 3 years ago
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    360-250 is the arc that angle BCD is facing soo; BCD = (360-250)/2 = 110/2 = 55 to me

  14. Sunshine447
    • 3 years ago
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    ohhhhhhhhhhhhhhhhhhhh okay, so it's 55 because it's half of the opposite arc?

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