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Can someone please help me with this? The lesson explains it, but I just don't get it..... Jerry inscribed a quadrilateral ABCD in a circle, as shown below. If the measure of arc BCD is 250°, what is the measure of angle BCD?

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cant link directly to flvs
It's from the lesson...

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Other answers:

notice that the angle at c ison the edge of the circle; there is a property that says this angle is half the arc across from it
where does the 250 come from?
BCD = 250 is stated in the question ....
The inscribed quadrilateral theorem?
i got no idea what its spose to be called :)
okay haha
I got 10 and 5 when I solved the part you wrote....... @amistre64
360-250 is the arc that angle BCD is facing soo; BCD = (360-250)/2 = 110/2 = 55 to me
ohhhhhhhhhhhhhhhhhhhh okay, so it's 55 because it's half of the opposite arc?

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