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The link doesn't work
it works on mine
This link works for you because it is on a course website and you have to be logged in to view it, do you know how to take a screenshot?
umm i think lemme try
Okay if you need help, reply back with your computer OS(Operating System, Mac or Windows)
a radius is always positive
that rules out 2 of your choices
so it's either B or C, but I still don't know which
the (x,y) pair at the center will make the (x-a)^2 and (y-b)^2 terms zero does that make sense?
not really, no...
usually they say (x-h)^2 + (y-k)^2 = r^2 and the center is at (h,k) with radius r
how do we get h and k?
so if you see (x- 1/2) that means the x value of the center is +1/2
in this case you match your equation to the "generic" one match (x-h)^2 + (y-k)^2 = r^2 (x-1/2)^2 + (y + 1)^2 = 25/4
matching y-k to y+1 you have to rewrite y+1 as y - (-1) now you see y - k matches y - (-1) and k is -1
or remember that you want the y value that makes (y+1)^2 zero. that would be y= -1
so the Y is -1?
then it's C? Right?
Thank you soooooo much! I'm going to go write you a testimonial! haha