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Sunshine447
Group Title
I really don't get this lesson question:
Which statement is true for the circle?
http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/0800/0800_G8_Q29a.gif
Its center is at the ordered pair of 1 over 2, minus 1, and the radius is minus five over two units.
Its center is at the ordered pair of minus 1 over 2, 1, and the radius is five over two units.
Its center is at the ordered pair of 1 over 2, minus 1, and the radius is five over two units.
Its center is at the ordered pair of minus 1 over 2, 1, and the radius is minus five over two units.
 one year ago
 one year ago
Sunshine447 Group Title
I really don't get this lesson question: Which statement is true for the circle? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/0800/0800_G8_Q29a.gif Its center is at the ordered pair of 1 over 2, minus 1, and the radius is minus five over two units. Its center is at the ordered pair of minus 1 over 2, 1, and the radius is five over two units. Its center is at the ordered pair of 1 over 2, minus 1, and the radius is five over two units. Its center is at the ordered pair of minus 1 over 2, 1, and the radius is minus five over two units.
 one year ago
 one year ago

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Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@amistre64
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
The link doesn't work
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
it works on mine
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@AccessDenied
 one year ago

dread907 Group TitleBest ResponseYou've already chosen the best response.0
This link works for you because it is on a course website and you have to be logged in to view it, do you know how to take a screenshot?
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
umm i think lemme try
 one year ago

dread907 Group TitleBest ResponseYou've already chosen the best response.0
Okay if you need help, reply back with your computer OS(Operating System, Mac or Windows)
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
Here's the whole thing as pasted from the lesson
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
a radius is always positive
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
okay...?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
that rules out 2 of your choices
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
so it's either B or C, but I still don't know which
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
the (x,y) pair at the center will make the (xa)^2 and (yb)^2 terms zero does that make sense?
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
not really, no...
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
usually they say (xh)^2 + (yk)^2 = r^2 and the center is at (h,k) with radius r
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
how do we get h and k?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
so if you see (x 1/2) that means the x value of the center is +1/2
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in this case you match your equation to the "generic" one match (xh)^2 + (yk)^2 = r^2 (x1/2)^2 + (y + 1)^2 = 25/4
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
matching yk to y+1 you have to rewrite y+1 as y  (1) now you see y  k matches y  (1) and k is 1
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
or remember that you want the y value that makes (y+1)^2 zero. that would be y= 1
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
so the Y is 1?
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
then it's C? Right?
 one year ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
Thank you soooooo much! I'm going to go write you a testimonial! haha
 one year ago
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