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Sunshine447
Group Title
I really don't get this lesson question:
Which statement is true for the circle?
http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/0800/0800_G8_Q29a.gif
Its center is at the ordered pair of 1 over 2, minus 1, and the radius is minus five over two units.
Its center is at the ordered pair of minus 1 over 2, 1, and the radius is five over two units.
Its center is at the ordered pair of 1 over 2, minus 1, and the radius is five over two units.
Its center is at the ordered pair of minus 1 over 2, 1, and the radius is minus five over two units.
 2 years ago
 2 years ago
Sunshine447 Group Title
I really don't get this lesson question: Which statement is true for the circle? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/0800/0800_G8_Q29a.gif Its center is at the ordered pair of 1 over 2, minus 1, and the radius is minus five over two units. Its center is at the ordered pair of minus 1 over 2, 1, and the radius is five over two units. Its center is at the ordered pair of 1 over 2, minus 1, and the radius is five over two units. Its center is at the ordered pair of minus 1 over 2, 1, and the radius is minus five over two units.
 2 years ago
 2 years ago

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Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@amistre64
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 2 years ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
The link doesn't work
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
it works on mine
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
@AccessDenied
 2 years ago

dread907 Group TitleBest ResponseYou've already chosen the best response.0
This link works for you because it is on a course website and you have to be logged in to view it, do you know how to take a screenshot?
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
umm i think lemme try
 2 years ago

dread907 Group TitleBest ResponseYou've already chosen the best response.0
Okay if you need help, reply back with your computer OS(Operating System, Mac or Windows)
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
Here's the whole thing as pasted from the lesson
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
a radius is always positive
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
okay...?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
that rules out 2 of your choices
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
so it's either B or C, but I still don't know which
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
the (x,y) pair at the center will make the (xa)^2 and (yb)^2 terms zero does that make sense?
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
not really, no...
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
usually they say (xh)^2 + (yk)^2 = r^2 and the center is at (h,k) with radius r
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
how do we get h and k?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
so if you see (x 1/2) that means the x value of the center is +1/2
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
in this case you match your equation to the "generic" one match (xh)^2 + (yk)^2 = r^2 (x1/2)^2 + (y + 1)^2 = 25/4
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
matching yk to y+1 you have to rewrite y+1 as y  (1) now you see y  k matches y  (1) and k is 1
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.1
or remember that you want the y value that makes (y+1)^2 zero. that would be y= 1
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
so the Y is 1?
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
then it's C? Right?
 2 years ago

Sunshine447 Group TitleBest ResponseYou've already chosen the best response.0
Thank you soooooo much! I'm going to go write you a testimonial! haha
 2 years ago
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