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daniceko

  • 2 years ago

Help? ill give medal :) Show your work Write a balanced net ionic equation for the following reaction. H3PO4(aq) + Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l)

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  1. daniceko
    • 2 years ago
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    @kelly226 can you help

  2. BluFoot
    • 2 years ago
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    I'll help :) So you want to try and have the same number of each element on each side. This is a pretty tricky one. It looks like you have twice as many P on the right as on the left side. So try adding a 2 in front of H3PO4 on the left side as a starter!

  3. daniceko
    • 2 years ago
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    This is really confussing for me so now i have 2 H3PO4(aq) + Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l)

  4. BluFoot
    • 2 years ago
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    If you're REALLY confused, you should start with easier questions, this one's pretty tricky. So good now try the same thing with Ca. You have 3 Ca on the right and 1 on the left.

  5. daniceko
    • 2 years ago
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    So would i put the 2 in front of the Ca like this? 2 H3PO4(aq) + 2Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l) and btw there is no easier questions on the packet this is the only one like this

  6. BluFoot
    • 2 years ago
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    3* :) not 2 this time

  7. BluFoot
    • 2 years ago
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    So: 2 H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + H2O(l) Now count your H's and O's on both sides and see if they're the same.

  8. daniceko
    • 2 years ago
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    I think the Os are the same but are the Hs the same

  9. BluFoot
    • 2 years ago
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    So do it carefully. 2H3PO4 has 2*3 = 6 H and 2*4=8 O 3Ca(OH)2 has 3*2 = 6 H and 3*2 = 6 O So the left side has 14 O and 12 H Ca3(PO4)2 has 4*2 = 8 O H2O has 2H and 1 O So the right side has 9 O and 2 H So the right side has way less Os and Hs. Can you figure out how to balance that out?

  10. daniceko
    • 2 years ago
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    In order to balance it out i have to add 5 o and 10 H some how right

  11. BluFoot
    • 2 years ago
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    Exactly! How can you get that?

  12. BluFoot
    • 2 years ago
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    Hint: use H2O

  13. daniceko
    • 2 years ago
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    could i add 5 to the H2O n the right end

  14. BluFoot
    • 2 years ago
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    Yes :) When you're adding 5 make sure you're adding 5 to 1. So the final thing should be 6H2O.

  15. daniceko
    • 2 years ago
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    Yay :) so now I have 2 H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + 6H2O

  16. BluFoot
    • 2 years ago
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    That's the final answer! You can check it by counting everything of course. I started with P and Ca because they're only present in one of the compounds on each side, so they're easier to balance. Try to do the same when working on other problems.

  17. daniceko
    • 2 years ago
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    Thank You so much your a genious :) But what about earlier when they were un equal bc of 5 o and 10 H I added the 5 ut what about the 10

  18. BluFoot
    • 2 years ago
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    Kinda hard to understand you there :P But you added 5 H2O. So you added 5*2=10 H and 5 O. Exactly what you needed.

  19. daniceko
    • 2 years ago
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    Ok I understand now thank you so much for your help

  20. BluFoot
    • 2 years ago
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    You are very welcome

  21. BluFoot
    • 2 years ago
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    That's what he wrote. Except an arrow instead of the = sign. It's a reaction, not an equation.

  22. daniceko
    • 2 years ago
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    wait is there (aq) in the final equation?

  23. daniceko
    • 2 years ago
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    @BluFoot is there (aq) in the final equation?

  24. BluFoot
    • 2 years ago
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    The states don't change when you balance the equation. So 2 H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + 6H2O (l) is correct

  25. daniceko
    • 2 years ago
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    oh ok thanks

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