anonymous
  • anonymous
Help? ill give medal :) Show your work Write a balanced net ionic equation for the following reaction. H3PO4(aq) + Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l)
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@kelly226 can you help
anonymous
  • anonymous
I'll help :) So you want to try and have the same number of each element on each side. This is a pretty tricky one. It looks like you have twice as many P on the right as on the left side. So try adding a 2 in front of H3PO4 on the left side as a starter!
anonymous
  • anonymous
This is really confussing for me so now i have 2 H3PO4(aq) + Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l)

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anonymous
  • anonymous
If you're REALLY confused, you should start with easier questions, this one's pretty tricky. So good now try the same thing with Ca. You have 3 Ca on the right and 1 on the left.
anonymous
  • anonymous
So would i put the 2 in front of the Ca like this? 2 H3PO4(aq) + 2Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l) and btw there is no easier questions on the packet this is the only one like this
anonymous
  • anonymous
3* :) not 2 this time
anonymous
  • anonymous
So: 2 H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + H2O(l) Now count your H's and O's on both sides and see if they're the same.
anonymous
  • anonymous
I think the Os are the same but are the Hs the same
anonymous
  • anonymous
So do it carefully. 2H3PO4 has 2*3 = 6 H and 2*4=8 O 3Ca(OH)2 has 3*2 = 6 H and 3*2 = 6 O So the left side has 14 O and 12 H Ca3(PO4)2 has 4*2 = 8 O H2O has 2H and 1 O So the right side has 9 O and 2 H So the right side has way less Os and Hs. Can you figure out how to balance that out?
anonymous
  • anonymous
In order to balance it out i have to add 5 o and 10 H some how right
anonymous
  • anonymous
Exactly! How can you get that?
anonymous
  • anonymous
Hint: use H2O
anonymous
  • anonymous
could i add 5 to the H2O n the right end
anonymous
  • anonymous
Yes :) When you're adding 5 make sure you're adding 5 to 1. So the final thing should be 6H2O.
anonymous
  • anonymous
Yay :) so now I have 2 H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + 6H2O
anonymous
  • anonymous
That's the final answer! You can check it by counting everything of course. I started with P and Ca because they're only present in one of the compounds on each side, so they're easier to balance. Try to do the same when working on other problems.
anonymous
  • anonymous
Thank You so much your a genious :) But what about earlier when they were un equal bc of 5 o and 10 H I added the 5 ut what about the 10
anonymous
  • anonymous
Kinda hard to understand you there :P But you added 5 H2O. So you added 5*2=10 H and 5 O. Exactly what you needed.
anonymous
  • anonymous
Ok I understand now thank you so much for your help
anonymous
  • anonymous
You are very welcome
anonymous
  • anonymous
That's what he wrote. Except an arrow instead of the = sign. It's a reaction, not an equation.
anonymous
  • anonymous
wait is there (aq) in the final equation?
anonymous
  • anonymous
@BluFoot is there (aq) in the final equation?
anonymous
  • anonymous
The states don't change when you balance the equation. So 2 H3PO4(aq) + 3Ca(OH)2(aq) -> Ca3(PO4)2(aq) + 6H2O (l) is correct
anonymous
  • anonymous
oh ok thanks

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