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x^2-7x-6=0?

\[x = \frac{ -b \pm \sqrt{b ^{2} -4ac} }{ 2a}\]

yes it is an exponent

x2 = a
-7x = b
-6 = c
x2 = 1
-7x = -7
-6 = -6

Hmm, ok thanks, let me work this out and I will reply to what I got to check if it is right.

|dw:1354234621716:dw|

Are you able to identify the variables a, b, and c and make the substitutions?

Yes, I got to the step that winterfezz last showed, but I don't know what to do now

Start with the expression within the radical. Start with (-7)^2. That is the same as 7^2.

|dw:1354234898685:dw|
you get 2 answers

And when you have a negative number times a positive number, the product will be negative.

So, can you determine (-7)^2 ?

(-7)^2 is the same as (-7)(-7) and that is the same as (7)(7)

That's good!. Because that is your final answer! Well done!

So I do not simplify it further?

That's as far as you can take it.

It is customary to leave it with the +- sign

Ok, so no decimal needed, I just leave it as this?

That's good just like that.

Thank both of you very much!:)

\[\frac{ 7\pm \sqrt{73} }{ 2 }\]Like that

You're very welcome!