anonymous
  • anonymous
Use the quadratic formula to solve the equation. x^2 – 7x – 6 = 0 Show work please.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
x^2-7x-6=0?
lilg132
  • lilg132
\[x = \frac{ -b \pm \sqrt{b ^{2} -4ac} }{ 2a}\]
anonymous
  • anonymous
yes it is an exponent

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lilg132
  • lilg132
x2 = a -7x = b -6 = c x2 = 1 -7x = -7 -6 = -6
anonymous
  • anonymous
\[x = \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]where a=1, b=-7, and c =-6 This is because your equation is in the standard form of ax^2 + bx + c = 0. So, now, just make the substitutions.
anonymous
  • anonymous
Hmm, ok thanks, let me work this out and I will reply to what I got to check if it is right.
anonymous
  • anonymous
Hint: after you make your substitutions, pay special attention to the expression within the radical (the square root sign). You will see that the numbet in the radical is positive, so you will have two real solutions. But your final solution will have a radical in it.
anonymous
  • anonymous
|dw:1354234621716:dw|
anonymous
  • anonymous
Are you able to identify the variables a, b, and c and make the substitutions?
anonymous
  • anonymous
Yes, I got to the step that winterfezz last showed, but I don't know what to do now
anonymous
  • anonymous
Start with the expression within the radical. Start with (-7)^2. That is the same as 7^2.
anonymous
  • anonymous
|dw:1354234898685:dw| you get 2 answers
anonymous
  • anonymous
And when you have a negative number times a positive number, the product will be negative.
anonymous
  • anonymous
So, can you determine (-7)^2 ?
anonymous
  • anonymous
(-7)^2 is the same as (-7)(-7) and that is the same as (7)(7)
anonymous
  • anonymous
Yes, tcarroll, I know all that basic math stuff xD I am at the part where I have |dw:1354235055422:dw|
anonymous
  • anonymous
That's good!. Because that is your final answer! Well done!
anonymous
  • anonymous
So I do not simplify it further?
anonymous
  • anonymous
That's as far as you can take it.
anonymous
  • anonymous
It is customary to leave it with the +- sign
anonymous
  • anonymous
Ok, so no decimal needed, I just leave it as this?
anonymous
  • anonymous
That's good just like that.
anonymous
  • anonymous
Thank both of you very much!:)
anonymous
  • anonymous
\[\frac{ 7\pm \sqrt{73} }{ 2 }\]Like that
anonymous
  • anonymous
You're very welcome!

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