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ajb44612
 3 years ago
how do you use the substitution method for 5x+3y=7 and y=x3
ajb44612
 3 years ago
how do you use the substitution method for 5x+3y=7 and y=x3

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CalebBeavers
 3 years ago
Best ResponseYou've already chosen the best response.0You know y=x+3 so put x3 in for y in the other equations and solve for x 5x+3(x3)=7 then use x to solve for y

ajb44612
 3 years ago
Best ResponseYou've already chosen the best response.0ok, so after you write 5x+3(x3)=7 then what do you do from there?

lilg132
 3 years ago
Best ResponseYou've already chosen the best response.1you replace y with the equation given so 5x + 3y =7 y = x  3 so it will now be 5x + 3(x  3) = 7 expand it 5x + 3x  9 = 7 bring the numbers to one side and letters on the other 5x + 3x = 7 + 9 8x = 16 now divide 8x by 8 to get x on its own but you have to do it to both sides 8x / 8 = 16 / 8 x = 2

lilg132
 3 years ago
Best ResponseYou've already chosen the best response.1now we know what the value of x is we can work out y 5x + 3y =7 so 5(2) + 3y = 7 expand the bracket 10 + 3y = 7 now move numbers to one side and letters to the other 3y = 7  10 3y = 3 divide both sides by 3 to get y on its own 3y / 3 = 3 / 3 y = 1 DONT FORGET TO CLICK BEST RESPONSE =)

ajb44612
 3 years ago
Best ResponseYou've already chosen the best response.0ok thanks so much! ok so i have a couple more i might need help with....so how bout 3x+2y=11 and x+y=4?

ajb44612
 3 years ago
Best ResponseYou've already chosen the best response.0can someone please help!
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