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dimsonrichelle Group Title

Find the apparent weight of an object fully submerged in water if its volume is 2m^3 and its density is 4000kg/m^3.

  • one year ago
  • one year ago

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  1. dimsonrichelle Group Title
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    I know that apparent weight is the weight that the scale has to support. Also I know there are three forces acting upon the object: buoyancy and tension frm the scale going upwards while the weight is going downwards.

    • one year ago
  2. dimsonrichelle Group Title
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    i am just really confused about what equations to use---

    • one year ago
  3. raphasuisse Group Title
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    (Gravitionnal) weight = P = mg = Vdg = 2*4000*10=80 000 N

    • one year ago
  4. raphasuisse Group Title
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    Buoyant force = Vd(water)g=2*1000*10=20 000 N

    • one year ago
  5. raphasuisse Group Title
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    So the apparent weight is P-(Buoyant Force) = 80 000 - 20 000 = 60 000 N

    • one year ago
  6. dimsonrichelle Group Title
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    so for buoyant force it's always referring to the use of water's density and not the object's density?

    • one year ago
  7. raphasuisse Group Title
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    Yes indeed. Par le principe d'Archimède, ''Tout corps plongé dans un fluide subit de la part de ce fluide une poussée verticale, orientée vers le haut, dont la valeur est égale au poids du volume de fluide déplacé''.

    • one year ago
  8. raphasuisse Group Title
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    Which is french for:

    • one year ago
  9. raphasuisse Group Title
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    A body immersed in a fluid receives from the fluid a vertical thrust, facing upward, whose magnitude equals the weight of the displaced fluid.

    • one year ago
  10. raphasuisse Group Title
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    In this case, the fluid is water, so the the buoyancy thrust involves the density of water :)

    • one year ago
  11. dimsonrichelle Group Title
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    oh--- that makes sense. Thank you so much! ^_^

    • one year ago
  12. raphasuisse Group Title
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    No problem :)

    • one year ago
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