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dimsonrichelle

  • 2 years ago

Find the apparent weight of an object fully submerged in water if its volume is 2m^3 and its density is 4000kg/m^3.

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  1. dimsonrichelle
    • 2 years ago
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    I know that apparent weight is the weight that the scale has to support. Also I know there are three forces acting upon the object: buoyancy and tension frm the scale going upwards while the weight is going downwards.

  2. dimsonrichelle
    • 2 years ago
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    i am just really confused about what equations to use---

  3. raphasuisse
    • 2 years ago
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    (Gravitionnal) weight = P = mg = Vdg = 2*4000*10=80 000 N

  4. raphasuisse
    • 2 years ago
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    Buoyant force = Vd(water)g=2*1000*10=20 000 N

  5. raphasuisse
    • 2 years ago
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    So the apparent weight is P-(Buoyant Force) = 80 000 - 20 000 = 60 000 N

  6. dimsonrichelle
    • 2 years ago
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    so for buoyant force it's always referring to the use of water's density and not the object's density?

  7. raphasuisse
    • 2 years ago
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    Yes indeed. Par le principe d'Archimède, ''Tout corps plongé dans un fluide subit de la part de ce fluide une poussée verticale, orientée vers le haut, dont la valeur est égale au poids du volume de fluide déplacé''.

  8. raphasuisse
    • 2 years ago
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    Which is french for:

  9. raphasuisse
    • 2 years ago
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    A body immersed in a fluid receives from the fluid a vertical thrust, facing upward, whose magnitude equals the weight of the displaced fluid.

  10. raphasuisse
    • 2 years ago
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    In this case, the fluid is water, so the the buoyancy thrust involves the density of water :)

  11. dimsonrichelle
    • 2 years ago
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    oh--- that makes sense. Thank you so much! ^_^

  12. raphasuisse
    • 2 years ago
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    No problem :)

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