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y = 4 - x
3x + 2(4 - x) = 11
3x + 8 - 2x = 11
3x - 2x = 11 - 8
x = 3

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3(3) + 2y = 11
9 + 2y = 11
2y = 11 - 9
2y = 2
y = 1

how do you find the substitution method for 5x-3y=5 and 10x+6y=20?

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