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ajb44612

  • 3 years ago

how do yo find the substitution method for 5x-3y=5 and 10x+6y=20? 2x-3y=2 and 4x-6=9? 2x+4y=12 and 6x+12y=36?

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  1. lilg132
    • 3 years ago
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    you dont click best response when i answer so i refuse to answer =)

  2. ajb44612
    • 3 years ago
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    i just did, so answer the question, please!

  3. Nimarta
    • 3 years ago
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    Substitution means solving one equation for x or y then plugging it into another equation. Though I would use the elimination method for both of these systems. For the first system, multiply (5x+3y=25) by -2 and you will get -10x+-6y=-50. Then u can cancel out the 10x and -10x. In the second system, multiply -3

  4. lilg132
    • 3 years ago
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    what about the previous question i answered !

  5. Nimarta
    • 3 years ago
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    hey im gonna delete my answer now since u gave the best response to someone else.... jk :)

  6. ajb44612
    • 3 years ago
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    i dont hab alot time so can you guys just help me........

  7. Nimarta
    • 3 years ago
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    i did. look at my answer, does it help or do u need more clarification?

  8. ajb44612
    • 3 years ago
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    uhm i need more clarification, like step by step....

  9. Nimarta
    • 3 years ago
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    ok eq 1) (5x+3y=25) * -2= -10x + -6y =-50 eq 2) 10x + 6y = 20 the 10x and the -10x cancel out to zero. as well as the -6y and the 6y.

  10. lilg132
    • 3 years ago
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    baisically you want the answer?

  11. ajb44612
    • 3 years ago
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    yes

  12. Nimarta
    • 3 years ago
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    for the first system the answer is (-1, 3/10)

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